<span>1 drop is approximately 0.05mL. Since 0.500L of 0.550M NH4Cl contains 0.275mol of substance (calculated by using c=n/V formula), equal amount of substance of NH3 is needed to neutralize this solution (since pH of 7 is neutral solution). Thus, we need 0.0275L of NH3, i.e. around 550 drops.</span>
Answer:
Explanation:
Seven of these isomers having similar pKa values are as follows
1) CH₃ -CH(CH₃)-CH(NO₂)-CH₃
2 ) CH₃ -(CH₂)-CH(NO₂)-CH₂-CH₃
3 ) CH₃ -CH₂-CH₂-CH₂-CH₂-NO₂
4 ) CH₃ -CH₂-CH₂-CH(NO₂)-CH₃
5 )CH₃ -CH(CH₃)(NO₂)-CH₂-CH₃
6 ) CH₃ -CH(CH₃)-CH₂-CH₂-NO₂
7)CH₃ -CH₂-CH₂-CH(CH₃)-NO₂
CH₃-C(CH₃)₂-NO₂
The last isomer has different PKa value because of tertiary carbon attached to nitro group.