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spin [16.1K]
3 years ago
6

Calculate the number of molecules found in 35 g of Sodium Hydroxide?

Chemistry
2 answers:
Helen [10]3 years ago
7 0

Answer:

5.27*10^23 (rounded to 3 significant figures)

Explanation:

The amount of molecules in one mole of anything is equal to Avogadro's number: 6.022×10^23

To find the number of moles of NaOH in 35 grams of it, do 35 divided by the molar mass (39.997): 35/39.997=0.87506562 moles of NaOH

To find the number of molecules, multiply the moles of NaOH by Avogadro's number: 0.87506562×(6.022×10^23)=5.26964522*10^23

inn [45]3 years ago
4 0

Answer:

5.27x10²³ molecules

Explanation:

In order to solve this problem we first <u>convert 35 g of Sodium Hydroxide (NaOH) into moles</u>, using its <em>molar mass</em>:

  • 35 g ÷ 40 g/mol = 0.875 mol

Finally we<u> convert 0.875 moles into number of molecules</u>, using <em>Avogadro's number</em>:

  • 0.875 mol * 6.023x10²³ molecules/mol = 5.27x10²³ molecules
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Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

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Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

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