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insens350 [35]
3 years ago
12

The leg's force forward on the foot= 500N

Physics
1 answer:
Anna11 [10]3 years ago
5 0

There's so much going on here, in a short period of time.

<u>Before the kick</u>, as the foot swings toward the ball . . .

-- The net force on the ball is zero.  That's why it just lays there and
does not accelerate in any direction.

-- The net force on the foot is 500N, originating in the leg, causing it to
accelerate toward the ball.


<u>During the kick</u> ... the 0.1 second or so that the foot is in contact with the ball ...

-- The net force on the ball is 500N.  That's what makes it accelerate from
just laying there to taking off on a high arc.

-- The net force on the foot is zero ... 500N from the leg, pointing forward,
and 500N as the reaction force from the ball, pointing backward. 

That's how the leg's speed remains constant ... creating a dent in the ball
until the ball accelerates to match the speed of the foot, and then drawing
out of the dent, as the ball accelerates to exceed the speed of the foot and
draw away from it.


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Two pipes of equal length are each open at one end. Each has a fundamental frequency of 470 Hz at 310 K. In one pipe the air tem
Tresset [83]

Answer:

Given:

Fundamental frequency: 470Hz

T1:310k,T2:315k

Calculating velocity

Recall v=(331m/s)✓[T1/273k)

V=331✓(310/273)

V1=331*(1.0656)=352.72m/s

V2=331✓(315/273)=355.5m/s

Fundamental frequency=4L

F2=F1(V2/V1)

F2=470(355.5/352.72)=474.4Hz

Beat=[F2-F1]=474.4-470=4.4Hz

Explanation:

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3 years ago
If you double the frequency of a vibrating object, its period:
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Answer:

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Explanation:

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Name two kinds of longitudinal waves and explain how you know they are longitudinal.
dezoksy [38]
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8 0
3 years ago
Two blocks of masses m and 3m are placed on a frictionless, horizontal surface. A light spring is attached to the more massive b
ivanzaharov [21]

Answer:

Explanation:

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3m x 2 = m  v

v = 6 m/s

Total kinetic energy

= 1/2 x .35 x 6 ² + 1/2 x 1.05 x 2 ²

= 8.4 J

This energy must be stored as elastic energy in the spring which was released as kinetic energy on burning the cord.

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4 0
3 years ago
A nature photographer is using a camera that has a lens with a focal length of 3.06 cm. The photographer is taking pictures of a
sleet_krkn [62]

Answer:

film is at distance of 3.07 cm from lens

Explanation:

Given data

focal length = 3.06 cm

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we apply here lens formula that is

1/f = 1/p + 1/q

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1/f = 1/p + 1/q

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q = 3.0690 cm

so film is at distance of 3.07 cm from lens

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