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3 years ago

What were clark's independent and dependent variables

2 answers:

7 0

His full name is dr Kenneth clark

what is being manipulated in the experiment
D.V. (dependent variable): what is being measured

Sloan [31]3 years ago

4 0

I cannot fully answer this question because you have not specifically defined who Clark is. If I knew his full name I might be able to help you more

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Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive

Burka [1]

Answer:

$1.91773\times 10^{37}\ kg$

Explanation:

v = Orbital speed = 130 km/s

d = Diameter = 16 ly

r = Radius = $\dfrac{d}{2}=\dfrac{16}{2}=8\ ly$

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

$1\ ly=9.461\times 10^{15}\ m$

As the centripetal force balances the gravitational energy we have the following relation

$\dfrac{GMm}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow M=\dfrac{v^2r}{G}\\\Rightarrow M=\dfrac{130000^2\times 8\times 9.461\times 10^{15}}{6.67\times 10^{-11}}\\\Rightarrow M=1.91773\times 10^{37}\ kg$

Mass of the the massive object at the center of the Milky Way galaxy is $1.91773\times 10^{37}\ kg$

4 0

3 years ago

Q.3. The equivalent resistance across AB is: (a)1 (c)2 (b)3 (d)4

sp2606 [1]

Answer:

1 ohm

Explanation:

First of all, the equivalent resistance for two resistors (r₁ and r₂) in parallel is given by:

1 / Eq = (1 / r₁) + (1 / r₂)

The equivalent resistance for resistance for two resistors (r₁ and r₂) in series is given by:

Eq = r₁ + r₂

Hence as we can see from the circuit diagram, 2Ω // 2Ω, and 2Ω // 2Ω, hence:

1/E₁ = 1/2 + 1/2

1/E₁ = 1

E₁ = 1Ω

1/E₂ = 1/2 + 1/2

1/E₂ = 1

E₂ = 1Ω

This then leads to E₁ being in series with E₂, hence the equivalent resistance (E₃) of E₁ and E₂ is:

E₃ = E₁ + E₂ = 1 + 1 = 2Ω

The equivalent resistance (Eq) across AB is the parallel combination of E₃ and the 2Ω resistor, therefore:

1/Eq = 1/E₃ + 1/2

1/Eq = 1/2 + 1/2

1/Eq = 1

Eq = 1Ω

7 0

3 years ago

Put on the ground a shrimp that has just been taken out of water.Now touch the shrimp from a distance by a stick.The shrimp will

Assoli18 [71]

Answer: Yes.

Explanation:

8 0

3 years ago

You use 350 W of power to move a 7.0 N object 5 m. How long did it take?

PilotLPTM [1.2K]

Answer:

0.1 second

Explanation:

We are given;

Power; P = 350 W

Force; F = 7 N

Distance; d = 5 m

Formula for power is;

P = workdone/time taken

Workdone = F × d

Thus;

350 = (7 × 5)/t

t = 35/350

t = 0.1 second

4 0

3 years ago

A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 85.0 m/s2

sergey [27]

Answer:

Maximum height attained by the model rocket is 2172.87 m

Explanation:

Given,

Initial speed of the model rocket = u = 0
acceleration of the model rocket = $a\ =\ 85.0 m/s^2$
time during the acceleration = t = 2.30 s

We have to consider the whole motion into two parts

In first part the rocket is moving with an acceleration of a = 85.0 $m/s^2$ for the time t = 2.30 s before the fuel abruptly runs out.

Let $s_1$ be the height attained by the rocket during this time intervel,

$s_1\ =\ ut\ +\ \dfrac{1}{2}at^2\\\Rightarrow s_1\ =\ 0\ +\ 0.5\times 85\times 2.30^2\\\Rightarrow s_1\ =\ 224.825\ m$

And Final velocity at that point be v

$\therefore v\ =\ u\ +\ at\\\Rightarrow v\ =\ 0\ +\ 85.0\times 2.3\\\Rightarrow v\ =\ 195.5\ m/s.$

Now, in second part, after reaching the altitude of 224.825 m the fuel abruptly runs out. Therefore rocket is moving upward under the effect of gravitational acceleration,

Let ' $s_2$ ' be the altitude attained by the rocket to reach at the maximum point after the rocket's fuel runs out,

At that insitant,

initial velocity of the rocket = v = 195.5 m/s.

a = $-g\ =\ -9.81\ m/s^2$
Final velocity of the rocket at the maximum altitude = $v_f\ =\ 0$

From the kinematics,

$v^2\ =\ u^2\ +\ 2as\\\Rightarrow 0\ =\ u^2\ -\ 2gs_2\\\Rightarrow s_2\ =\ \dfrac{u^2}{2g}\\\Rightarrow s_2\ =\ \dfrac{195.5^2}{2\times 9.81}\\\Rightarrow s_2\ =\ 1948.02\ m$

Hence the maximum altitude attained by the rocket from the ground is

$s\ =\ s_1\ +\ s_2\ =\ 224.85\ +\ 1948.02\ =\ 2172.87\ m$

6 0

3 years ago