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kolbaska11 [484]

2 years ago

10

The sample of oxygen which represents the greatest mass is

2 answers:

Lerok [7]2 years ago

8 0

Answer:

A

Explanation:

Readme [11.4K]2 years ago

7 0

A sorry if not correct

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In the article "A Sea of Garbage" what message is each cartoon trying to convey to readers? Do they succeed?

sertanlavr [38]

Answer:

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8 0

3 years ago

An object was measured by a worker as

marusya05 [52]

<h2>Answer - 0.73%</h2>

14.6 .2

=

100 x

(Above is proportions I used to get the answer)

x = 0.73% which is the answer.

6 0

3 years ago

Read 2 more answers

C2H4(g) + H2(g) ----> C2H6(g)

sertanlavr [38]

D because wants you add the equation it should increase temp but decrease the value in pressure

4 0

3 years ago

aspirin C6H4(CO2)(CO2CH3),can be prepared in the chemistry laboratory by the reactions of salicylic acid, C6H4(CO2H)(OH),with ac

Ket [755]

262mol 1=kg
g=1000
from stoichoimetry

x=102*1000/360
x=102000/360
x=283.33

density =m/v
=283.33/1.082
=262mol

8 0

3 years ago

Hoochie [10]

a. volume of NO : 41.785 L

b. mass of H2O : 18 g

c. volume of O2 : 9.52 L

<h3>Further explanation</h3>

Given

Reaction

4 NH₃ (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)

Required

a. volume of NO

b. mass of H2O

c. volume of O2

Solution

Assume reactants at STP(0 C, 1 atm)

Products at 1000 C (1273 K)and 1 atm

a. mol ratio NO : O2 from equation : 4 : 5, so mo NO :

$\tt \dfrac{4}{5}\times 0.5=0.4$

volume NO at 1273 K and 1 atm

$\tt V=\dfrac{nRT}{P}=\dfrac{0.4\times 0.08206\times 1273}{1}=41.785~L$

b. 15 L NH3 at STP ( 1mol = 22.4 L)

$\tt \dfrac{15}{22.4}=0.67~mol$

mol ratio NH3 : H2O from equation : 4 : 6, so mol H2O :

$\tt \dfrac{6}{4}\times 0.67=1$

mass H2O(MW = 18 g/mol) :

$\tt mass=mol\times MW=1\times 18=18~g$

c. mol NO at 1273 K and 1 atm :

$\tt n=\dfrac{PV}{RT}=\dfrac{1\times 35.5}{0.08206\times 1273}=0.34$

mol ratio of NO : O2 = 4 : 5, so mol O2 :

$\tt \dfrac{5}{4}\times 0.34=0.425$

Volume O2 at STP :

$\tt 0.425\times 22.4=9.52~L$

5 0

3 years ago