Answer:
It will take both pumps 3.08 hours to fill the tank working together.
Explanation:
Pump A can fill the tank in 5 hours. Assuming that the pump gives out a steady flow of water, in one hour, pump A can fill 1/5th of the tank. Similarly, pump B in an hour, fills up 1/8th of the tank.
We must add up these two values, in order to find how much of the tank the two pumps can fill up together in one hour.
1/5 +1/8 =13/40
So 13/40 of the tank is filled in an hour. We need to find how many hours it will take for the entire tank to be filled. To do so, divide 40 by 13. This gives:
3.08 hours to fill up the tank.
The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.
<h3>
Linear expansivity </h3>
The temperature to which it must be heated in order to fit the shaft is calculated as follows;

where;
- ΔT is change in temperature
- ΔL is change in length = 50.04 mm - 50 mm = 0.04 mm
- α is coefficient of linear expansion
- L is original length
ΔT = (0.04)/(50 x 15 x 10⁻⁶)
ΔT = 53.3 ⁰C
<h3>Final temperature</h3>
T₂ - T₁ = ΔT
T₂ = ΔT + T₁
where;
- T₂ is final temperature
- T₁ is initial temperature
T₂ = 53.3 + 20
T₂ = 73.33 ⁰C
Learn more about linear expansivity here: brainly.com/question/14325928
#SPJ1
Complete question:
A taut rope has a mass of 0.123 kg and a length of 3.54 m. What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m if the waves are to travel at 28.0 m/s ?
Answer:
The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.
Explanation:
Velocity = Frequency X wavelength
V = Fλ ⇒ F = V/λ
F = 28/0.6 = 46.67 Hz
Angular frequency (ω) = 2πF = 2π (46.67) = 93.34π rad/s
Average power supplied to the rope will be calculated as follows

where;
ω is the angular frequency
A is the amplitude
V is the velocity
μ is mass per unit length = 0.123/3.54 = 0.0348 kg/m
= 1676.159 watts
The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.
The change in the total energy of the object is zero (0).
The given parameters:
work done by the machine, W = 50 J
mass of the object, m = 10 kg
To find:
the change in the total energy of the object
The change in the total energy of the object is the difference between the objects initial energy due to its position and the work done on the object.
Based on work energy-theory, the work done on the object is equal to the energy of the object.
- The energy of the object = work-done on the object
- The change in total energy = 50 J - 50 J = 0
Thus, the change in the total energy of the object is zero (0).
Learn more here: brainly.com/question/20377140