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pochemuha
3 years ago
11

I need help PLEASE HEEEEEEEEELPP

Physics
1 answer:
lana66690 [7]3 years ago
6 0

Answer:

a = (v2 - v1) / t

From A to B    (8 - 4) m/s / 1 s = 4 m / s^2

From A to D    ( 7 - 4) m/s / 5 s = .6 m / s^2

Note these equations hold for "uniform" values

They say nothing about the acceleration at intermediate points - the equation just says that his average speed increased from 4 m/s to 7 m/s during a 5 sec period

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Answer:

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The equal and opposite forces that is applied on the pen keeps the pen still on the table.

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3 years ago
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A 5.67-kg block of wood is attached to a spring with a spring constant of 150 N/m. The block is free to slide on a horizontal fr
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Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

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The maximum acceleration of upper block can be μ g.

 a= μ g                          ( g = 10 m/s²)

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μ g  =ω²X

We know for spring mass system natural frequency given as

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By putting the values

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By putting the values

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