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tatiyna
3 years ago
14

Describe a way to separate iron filings from sand.

Chemistry
2 answers:
nikklg [1K]3 years ago
8 0
Use a magnet to separate the iron from the sand.
Alexxandr [17]3 years ago
4 0
Spread out the iron fillings
then since iron is magnetic use a magnet to extract the iron fillings from the sand. if you want to separate the salt from the sand you add water to the sand mix it for a while and the salt will dissolve <span />
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What is the volume of a salt crystal measuring 1.64 x 10^-2m by 1.5 x 10^-2m by 4.8 x 10^-3
lubasha [3.4K]

Answer:

V = 1.2 × 10⁻⁶ m³

Explanation:

Volume is equal to length × width × height, since we are given these measurements in the question we can simply plug our numbers into the formula.

V = l × w × h

V = 1.64 x 10⁻² × 1.5 x 10⁻² × 4.8 x 10⁻³

V = 1.2 × 10⁻⁶ m³

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Which of the following is true about cells?
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D

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Use the following equation to answer the questions below:
Gala2k [10]

Explanation:

The equation of the reaction is given as;

Be + 2HCl → BeCl2 + H2

What is the mass of beryllium required to produce 25.0g of beryllium chloride?

1 mol of Be produces 1 mol of BeCl2

Converting to mass;

Mass = Molar mass  *  Number of moles

9.01g of Be produces 79.92g of BeCl2

xg of Be produces 25g of BeCl2

Solving for x;

x = 25 * 9.01 / 79.92

x = 2.82 g

What is the mass of hydrochloric acid required to produce 25.0g of beryllium chloride? g

Converting 25.0g of beryllium chloride to moles;

Number of moles = Mass / Molar mass

Number of moles = 25 / 79.92 = 0.3128 mol

2 mol of HCl produces 1 mol of BeCl2

x mol of HCl would produce 0.3128 mol of BeCl2

solving for x;

x = 0.3128 * 2 = 0.6256 mol

Converting to mass;

Mass = 0.6256 * 36.5 = 22.83 g

What is the mass of hydrogen gas produced when 25.0g of beryllium chloride is also produced? g

25g of BeCl2 = 0.3128 mol of BeCl2

From the equation;

1 mol of H2 is produced alongside 1 mol of BeCl2

This means;

0.3128 mol of H2 would also be produced alongside 0.3128 mol of BeCl2

Mass = Number of moles * Molar mass

Mass = 0.3128mol * 2.0159 g/mol = 0.6306 g

3 0
3 years ago
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