Answer with explanation:
We are given that
Mass of ball,75 g=
1 kg=1000 g
Height,
Horizontal velocity,
Mass of plate
a.Initial velocity of plate,
Velocity before impact=
Where
Velocity after impact,
According to law of conservation of momentum
Substitute the values
Velocity of plate=1.69 m/s
b.Initial energy=
Final energy=
Final energy=
Energy lost due to compact=Initial energy-final energy=1.326-1.162=0.164 J
The mechanical energy for the first and the second ball is
Mass of the first ball = 20 kg
The initial speed at which a cannonball is fired from a cannon =1000 m/s
The angle made by the cannonball while being fired from the cannon = 37°
The maximum height reached by the first ball is,
The maximum height of the first cannonball is 17478.69 m.
The initial speed at which a cannonball is fired from a cannon =1000 m/s
The angle made by the cannonball while being fired from the cannon = 90 °
For the first ball, total mechanical energy= Potential energy at maximum height + kinetic energy at the maximum height
So, the total mechanical energy is,
= mgh \: + \frac{1}{2}mv {}^{2} _{x}[/tex]
Therefore, the total mechanical energy for the first and the
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Answer:
Option D is the correct answer.
Explanation:
Stress is the force per unit area that tend to change the shape of body.
Stress is defined as internal resistive force per unit area.
So, so stress distributed over an area is best described as internal resistive force.
Option D is the correct answer.