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valentinak56 [21]
3 years ago
12

Which of the following ratios are needed to determine the mass of oxygen produced from the decomposition of 10 grams of potassiu

m chlorate? Select all that apply. 2KClO3 → 2K + 3O2 Question 3 options: 1 mole KClO3112.55 g KClO3 31.998 g O21 mole O2 3 mole O22 mole KClO3 112.55 g KClO31 mole KClO3
Chemistry
1 answer:
Zielflug [23.3K]3 years ago
7 0

The ratios which are needed to determine the mass of oxygen produced from the decomposition of 10 grams of potassium chlorate are;

  • 31.998 g O2 : 1 mole O2
  • 3 mole O2 : 2 mole KClO3
  • 112.55 g KClO31 mole KClO3

From stoichiometry;

  • We can conclude that according to the reaction;

3 moles of oxygen requires 2 moles of KClO3 to be produced.

And from molar mass analysis;

  • 31.998 g O2 is equivalent to 1 mole O2
  • O2112.55 g KClO3 is equivalent to 1 mole KClO3

Read more:

brainly.com/question/9920155

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Answer: The number of grams of H_2 in 1620 mL is 1.44 g

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 1620 ml = 1.62 L  (1L=1000ml)

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K

n=\frac{PV}{RT}

n=\frac{1atm\times 16.2L}{0.0821Latm/K mol\times 273K}=0.72moles

Mass of hydrogen =moles\times {\text {Molar mass}}=0.72mol\times 2g/mol=1.44g

The number of grams of H_2 in 1620 mL is 1.44 g

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