Consider two lines. Line A is given by the function f(x) = 4x - 9, while Line B contains the points (0,5) and (2.12).

8. Write the equation of the line that is parallel to the line 2x + 5y = 15 and passes through the

marissa [1.9K]

Answer:

$\sf y = \bold -\frac{2}{5} x -3$

Explanation:

part A identification for slope:

$\sf 2x + 5y = 15$

$\sf 5y = -2x + 15$

$\sf y = \frac{-2x + 15}{5}$

$\sf y = -\frac{2 }{5} x+3$

comparing with slope intercept form: y = mx + b

we can find that here the slope is $\bold -\frac{2}{5}$

part B, solving the equation:

if the line is parallel, then the slope will be same.

given coordinates: ( - 10, 1 )

using the equation:

y - y₁ = m( x - x₁ )

$\sf y - 1 = \bold -\frac{2}{5} (x --10)$

$\sf y = \bold -\frac{2}{5} x -4 + 1$

$\sf y = \bold -\frac{2}{5} x -3$

Extra information:

check the image below. this proves that the line is parallel and passes through point (-10, 1). the blue line is question line and red the answer line.

3 0

2 years ago

Read 2 more answers

Find the 10th term of an arithmetic sequence if the common difference is 32 and the first term is 2

zaharov [31]

Answer:

290

Step-by-step explanation:

If the first term is 2 and the common difference is 32, then the formula for a(n) is:

a(n) = 2 + 32(n-1).

Thus, the 10th term is a(10) = 2 + 32(10-1) = 2 + 32(9) = 290

6 0

3 years ago

What is X if 2 times the square root of 2X-1 =4

svp [43]

Remove the radical by raising each side to the index of the radical.
x = 5/2

5 0

3 years ago

The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6

viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The proportion of contracts involved between five and 10 inclusive bidders is 0.5.

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders No. contracts Relative frequency of contracts

2 6 6/102=0.0588

3 20 20/102=0.1961

4 24 24/102=0.2353

5 18 18/102=0.1765

6 13 13/102=0.1275

7 7 7/102=0.0686

8 5 5/102=0.049

9 6 6/102=0.0588

10 2 2/102=0.0196

11 1 1/102=0.0098

Total 102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The proportion of contracts involved between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10= Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The proportion of contracts involved strictly between five and 10 bidders is 0.304.

8 0

3 years ago

Find the horizontal asymptote

eimsori [14]

Answer:

Correct answer: h = 3/5 or y = 3/5

Step-by-step explanation:

Given:

h(x) = (3x² - 9x - 4) / (5x² - 4x + 8)

h = lim x -> ∞ (3x² - 9x - 4) / (5x² - 4x + 8) the numerator and denominator will be divided by x² and get

h = lim x -> ∞ (3 - 9(1/x) - 4 (1/x²)) / (5 - 4(1/x) + 8 (1/x²)

The terms 1/x and 1/x² when x strives ∞ they strives 0

x -> ∞ ⇒ 1/x -> 0 and x -> ∞ ⇒ 1/x² -> 0

h = (3 - 0 - 0) / (5 - 0 + 0)

Horizontal asymptote is h = 3/5 or y = 3/5

God is with you!!!

5 0

3 years ago