All categories

3 years ago

________ cm = 3.34 m

Chemistry

2 answers:

fgiga [73]3 years ago

8 0

334
Multiple length by value

vodka [1.7K]3 years ago

7 0

Answer:

334

Explanation:

multiply the length value by 100

You might be interested in

A solution contains 5.25 g of urea, CO(NH2)2 (a nonvolatile solute) and 0.100 kg of water. If the vapor pressure of pure water a

babymother [125]

Answer:

The vapor pressure of the solution is 23.3 torr

Explanation:

Step 1: Data given

Mass of urea = 5.25 grams

Mass of water = 0.100 kg = 100 grams

Temperature = 25.0 °C

Vapor pressure of water = 23.7 torr

Step 2: Calculate moles of water

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 100 grams / 18.02 g/mol

Moles H2O = 5.55 moles

Step 3: Calculate moles of urea

Moles urea = 5.25 grams / 60.06 g/mol

Moles urea = 0.0874 moles

Step 4: Calculate mol fraction H2O

Mol fraction H2O = 5.55 moles / (5.55 + 0.0874)moles

Mol fraction H2O = 0.984

Step 5: calculate the vapor pressure of the solution

This means that you can use the mole fraction of water and the vapor pressure of pure water at 25° C to determine the vapor pressure of the solution.

Psol =Xwater * Pwater

⇒Psol = the vapor pressure of the solution

⇒Xwater =the mol fraction of water

⇒Pwater = the vapor pressure of pure water

Psol = 0.984 * 23.7 torr

Psol = 23.3 torr

The vapor pressure of the solution is 23.3 torr

3 0

4 years ago

What is the mass of Na2CO3 required to make a

Paladinen [302]

Answer:

21.2 g

Explanation:

Step 1: Given data

Molar concentration of the solution (C): 0.400 mol/L

Volume of solution (V): 500 mL (0.500 L)

Step 2: Calculate the moles of Na₂CO₃ (solute) in the solution

We will use the definition of molarity.

C = moles of solute / liters of solution

moles of solute = C × liters of solution

moles of solute = 0.400 mol/L × 0.500 L = 0.200 mol

Step 3: Calculate the mass corresponding to 0.200 moles of Na₂CO₃

The molar mass of Na₂CO₃ is 105.99 g/mol.

0.200 mol × 105.99 g/mol = 21.2 g

8 0

3 years ago

desicribe the relationship between an inner planets distance from the sun and its period of revolution?

Anit [1.1K]

Kepler’s third law exhibits the relationships between the distance of a planet from the sun and the period of its revolution. Kepler’s third law is also sometimes referred to as the law of harmonies.

Kepler’s third law compares the orbital period and the radius of an orbit of a planet to the distance of the planet to the sun. It states mathematically that the more distant a planet is from the sun the greater its orbital period will be. The period of revolution of a planet is measured in days, weeks, months or years. For example, Earth’s period of revolution is 365 days.

6 0

3 years ago

Consider the following balanced equation:

kow [346]

Answer:

The theoretical yield of Cu(s) in moles is 60.15 moles

Explanation:

Step 1: Data given

Number of moles CuO = 70.8 moles

Number of moles NH3 = 40.1 moles

Molar mass CuO = 79.545 g/mol

Molar mass NH3 = 17.03 g/mol

Step 2: The balanced equation

3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles

There will remain 70.8 - 60.15 = 10.65 moles CuO

Step 3: Calculate moles Cu

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

For 40.1 moles NH3 we'll have 60.15 moles Cu

The theoretical yield of Cu(s) in moles is 60.15 moles

8 0

4 years ago

It is desired to make 1.00 liter of 6.00 M nitric acid from concentrated 16.00 M HNO3.A) How many moles of nitric acid are in 1.

natima [27]

Answer:

A) 6.00 mol.

B) 0.375 L or 375 mL

C) 6.00 M

Explanation:

Hello,

A) In this case, from the definition of molarity, we compute the moles for the given volume and concentration:

$n=M*V=1.00L*6.00mol/L=6.00mol$

B) In this case, from the stock solution, the required volume is:

$V=\frac{6.00mol}{16.00mol/L}=0.375L$

C) In this case, we apply the following formula for dilution process:

$M_1V_1=M_2V_2$

Thus, solving for the final molarity, we obtain:

$M_2=\frac{M_1V_1}{V_2}=\frac{16.00M*0.375L}{1.00L}\\ \\M_2=6.00M$

Regards.

5 0

3 years ago