The FDA! (food and drug administration)
In Engineering, the thrust angle is checked by referencing: C. vehicle centerline.
<h3>What is a
thrust angle?</h3>
A thrust angle can be defined as an imaginary line which is drawn perpendicularly from the centerline of the rear axle of a vehicle, down the centerline.
This ultimately implies that, the thrust angle is a reference to the centerline (wheelbase) of a vehicle, and it confirms that the two wheels on both sides are properly angled within specification.
Read more on thrust angle here: brainly.com/question/13000914
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The first one is d or the 4th answer choice and the second one is false. Hope this helps!
Answer:
The shear strain is 0.05797 rad.
Explanation:
Shear strain is the ratio of change in dimension along the shearing load direction to the height of the plate under application of shear load. Width of the plate remains same. Length of the plate slides under shear load.
Step1
Given:
Height of the pad is 1.38 in.
Deformation at the top of the pad is 0.08 in.
Calculation:
Step2
Shear strain is calculated as follows:
![tan\phi=\frac{\bigtriangleup l}{h}](https://tex.z-dn.net/?f=tan%5Cphi%3D%5Cfrac%7B%5Cbigtriangleup%20l%7D%7Bh%7D)
![tan\phi=\frac{0.08}{1.38}](https://tex.z-dn.net/?f=tan%5Cphi%3D%5Cfrac%7B0.08%7D%7B1.38%7D)
![tan\phi= 0.05797](https://tex.z-dn.net/?f=tan%5Cphi%3D%200.05797)
For small angle of
,
can take as
.
![\phi = 0.05797 rad.](https://tex.z-dn.net/?f=%5Cphi%20%3D%200.05797%20rad.)
Thus, the shear strain is 0.05797 rad.
Answer:
the crown is false densty= 12556kg/m^3[/tex]
Explanation:
Hello! The first step to solve this problem is to find the mass of the crown, this is found using the weight of the crown in the air by means of the equation for the weight.
W=mg
W=weight(N)=31.4N
M=Mass
g=gravity=9.81m/S^2
solving for M
m=W/g
![m=\frac{31.4N}{9.81m/S^2}=3.2kg](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B31.4N%7D%7B9.81m%2FS%5E2%7D%3D3.2kg)
The second step is find the volume of crown remembering that when an object is weighed in the water the result is the subtraction between the weight of the object and the buoyant force of the water which is the product of the volume of the crown by gravity by density of water
![F=mg-\alpha V g](https://tex.z-dn.net/?f=F%3Dmg-%5Calpha%20%20V%20g)
Where
F=weight in water=28.9N
m=mass of crown=3.2kg
g=gravity=9.81m/S^2
α=density of water=1000kg/m^3
V= crown´s volume
solving for V
![V=\frac{mg-F }{g \alpha } =\frac{(3.2)(9.81)-28.9}{9.81(1000)} =0.000254m^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7Bmg-F%20%7D%7Bg%20%5Calpha%20%7D%20%3D%5Cfrac%7B%283.2%29%289.81%29-28.9%7D%7B9.81%281000%29%7D%20%3D0.000254m%5E3)
finally, we remember that the density is equal to the index between mass and volume
![\alpha =\frac{m}{v} =\frac{3.2}{0.000254} =12556kg/m^3](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cfrac%7Bm%7D%7Bv%7D%20%3D%5Cfrac%7B3.2%7D%7B0.000254%7D%20%3D12556kg%2Fm%5E3)
To determine the density of the crown without using the weight in the water and with a bucket we can use the following steps.
1.weigh the crown in the air and find the mass
2. put water in a cylindrical bucket and measure its height with a ruler.
3. Put the crown in the bucket and measure the new water level with a ruler.
4. Subtract the heights, and find the volume of a cylinder knowing the difference in heights and the diameter of the bucket, in order to determine the volume of the crown.
5. find density by dividing mass by volume