Which one is suitable for industries petrol engine or diesel engine and why?

What is the meaning of the measurement met?

san4es73 [151]

Answer: MET(Metabolic equivalent of task) is the measurement technique that is based on the ratio of the energy that is being spend by an individual by any physical activity to the energy spent by individual sitting in quiet position.

This ration has some reference in which is ratio is measured.The energy being measured in the activity time of the person considers his/her relative mass at that time. This relative mass is compared in accordance with the oxygen amount of 3.5 ml per kg/min that is almost equal to energy of the person in the sitting position.

6 0

3 years ago

Combining two strings is called

a_sh-v [17]

Answer:

The appropriate response is "Concatenation". A further explanation is given below.

Explanation:

Two or much more strings are almost always concatenated besides space-saving purposes, and therefore could be acknowledged as either a single product.
A straightforward example that demonstrates concatenation should be to figure out what it means. How and why that ends up making a term separate from several other phrases is that almost all the messages are stacked together without any open space between each one.

5 0

3 years ago

A reversible heat pump and a Carnot heat pump operate between the same two thermal reservoirs. Which heat pump has higher COP?

jonny [76]

Answer:

Both heat pump has same COP

Explanation:

Given that a reversible heat pump and a Carnot heat pump which is operating between the same temperature limits will have the same COP because the temperature limits are same, that is the source temperature and the sink temperature. Also because we know that a Carnot cycle is a totally reversible cycle. Therefore for a perfectly reversible Carnot cycle, the COP will be same for a reversible heat pump and a Carnot heat pump operating between two same thermal reservoirs.

Thus, both heat pump will have same COP.

4 0

4 years ago

It has been estimated that 139.2x10^6 m^2 of rainforest is destroyed each day. assume that the initial area of tropical rainfore

Dmitry [639]

Answer:

A. 6.96 x 10^-6 /day

B. 22.466 x 10^12 m^2

C. 9.1125 x 10^14 kg of CO2

Explanation:

A. Rate of rainforest destruction = 139.2 x 10^6 m^2/day

Initial area of the rainforest = 20 x 10^12 m^2

Therefore to calculate exponential rate in 1/day,

Rate of rainforest destruction/ initial area of rainforest

= 139.2 x 10^6/20 x 10^12

= 6.96 x 10^-6 /day

B. Rainforest left in 2015 using the rate in A.

2015 - 1975 = 40 years

(40 * 365 )days + 10 days (leap years)

= 14610 days

Area of rainforest in 1975 = 24.5 x 10^12m^2

Rate of rainforest destruction = 139.2 x 10^6 m^2/day

Area of rainforest in 2015 = 14610 * 139.2 x 10^6

= 2.034 x 10^12 m^2

Area left = area of rainforest in 1975 - area of rainforest destroyed in 40years

= 24.5 x 10^12 - 2.034 x 10^12

= 22.466 x 10^12 m^2

C. How much CO2 will be removed in 2025

Recall: Photosynthesis is the process of plants taking in CO2 and water to give glucose and O2.

So CO2 removed is the same as rainforest removed so we use the rate of rainforest removed in a day

Area of rainforest in 1975 = 24.5 x 10^12 m^2

Area of rainforest removed in 2025 = 18262 days * 139.2 x 10^6

= 2.54 x 10^12 m^2

Area of rainforest removed between 1975 - 2025 = 24.5 x 10^12 - 2.54 x 10^12

= 21.958 x 10^12 mC2 of rainforest removed

CO2 = 0.83kg/m^2.year

CO2 removed between 1975 - 2025 = 0.83 * 21.958 x 10^12 * 50 years

= 9.1125 x 10^14 kg of CO2 was removed between 1975 - 2025

6 0

3 years ago

Copy the file DiceSimulation.java (see Code Listing 4.1) from below these instructions. DiceSimulation.java is incomplete. Since

Aliun [14]

Answer:

Program Dice.java

=================================================

import java.util.Random;

public class Dice

{

private int spots; //the number of spots up on the die

private static Random generator;

//a random number generator use simulating rolling dice,

//shared by all dice, so that it will be as random as possible

//constructor creates a single die, inititally with no spots

public Dice()

{

//create an instance of the random

generator = new Random();

spots = 0;

}

//simulates rolling the die and stores the numbers rolled

public void roll()

{

//return 1,2,3,4,5, or 6

spots = generator.nextInt(6) + 1;

}

//return the value of the die

public int getSpots()

{

return spots;

}

=========================================================

Program DiceSimulation.java

=========================================================

public class DiceSimulation

{

public static void main(String [] args)

{

final int NUMBER = 10000; //the number of times the roll the dice

Dice die1 = new Dice(); //first die

Dice die2 = new Dice(); //second die

int die1Value; //the number of spots on the second die

int die2Value; //the number of spots on the first die

int count = 0; //number of times the dice were rolled

int snakeEye = 0; //number of times of snakes eyes is rolled

//number of times double two's, three's, four's, five's, six's

int twos = 0;

int threes = 0;

int fours = 0;

int fives = 0;

int sixes = 0;

//ENTER YOUR CODE FOR THE ALGORITHM HERE

for(count=0;count<=NUMBER;count++)

{

die1.roll();

int t1=die1.getSpots();

die2.roll();

int t2=die2.getSpots();

if(t1==t2)

{

if(t1==1)snakeEye++;

else if(t1==2)twos++;

else if(t1==3)threes++;

else if(t1==4)fours++;

else if(t1==5)fives++;

else if(t1==6)sixes++;

}

count--;

//output to console

System.out.println("You rolled snake eyes " + snakeEye