Answer:
E= 15 GPa.
Explanation:
Given that
Length ,L = 0.5 m
Tensile stress ,σ = 10.2 MPa
Elongation ,ΔL = 0.34 mm
lets take young modulus = E
We know that strain ε given as



We know that

Therefore the young's modulus will be 15 GPa.
Answer:
Find the answer in the attached in the order
Option a, Option c and Option b
Explanation:
Answer:
The mass of the air is 0.0243 kg.
Explanation:
Step1
Given:
Stroke of the cylinder is 320 mm.
Bore of the cylinder is 280 mm.
Pressure of the air is 101.3 kpa.
Temperature of the air is 13°C.
Step2
Calculation:
Stroke volume of the cylinder is calculated as follows:


V = 0.0197 m³.
Step3
Assume air an ideal gas with gas constant 287 j/kgK. Then apply ideal gas equation for mass of the air as follows:
PV=mRT


m= 0.0243 kg.
Thus, the mass of the air is 0.0243 kg.