Answer:
s= 20.4 m
Explanation:
First lets write down equations for each ball:
s=so+vo*t+1/2a_c*t^2
for ball A:
s_a=30+5*t+1/2*9.81*t^2
for ball B:
s_b=20*t-1/2*9.81*t^2
to find time deeded to pass we just put that
s_a = s_b
30+5*t-4.91*t^2=20*t-4.9*t^2
t=2 s
now we just have to put that time in any of those equations an get distance from the ground:
s = 30 + 5*2 -1/2*9.81 *2^2
s= 20.4 m
Answer:
The lowest point of the curve is at 239+42.5 ft where elevation is 124.16 ft.
Explanation:
Length of curve is given as

is given as

The K value is given from the table 3.3 for 55 mi/hr is 115. So the value of A is given as

A is given as

With initial grade, the elevation of PVC is

The station is given as

Low point is given as

The station of low point is given as

The elevation is given as

So the lowest point of the curve is at 239+42.5 ft where elevation is 124.16 ft.
no artical shoul be used here
Answer:
Web Browser
Explanation:
Because you dont use a messaging app or presentation software to look up stuff its common knowledge
...simplify devices, reducing weight and the chance of failure.