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Helen [10]
3 years ago
15

Which one is suitable for industries petrol engine or diesel engine and why?

Engineering
2 answers:
Vika [28.1K]3 years ago
7 0

Answer:

diesel engine

Explanation:

because diesel is way more strong than petrol

klio [65]3 years ago
3 0

Answer:

diesel engine

Explanation:

because diesel is stronger than petrol

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A cylinder of aluminum-magnesium alloy 0.5 m long is subjected to an elastic tensile stress of 10.2 MPa. The measured elastic el
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Answer:

E= 15 GPa.

Explanation:

Given that

Length ,L = 0.5 m

Tensile stress ,σ = 10.2 MPa

Elongation ,ΔL = 0.34 mm

lets take young modulus  = E

We know that strain ε given as

\varepsilon =\dfrac{\Delta L}{L}

\varepsilon =\dfrac{0.34}{0.5\times 1000}

\varepsilon =0.00068

We know that

\sigma = \varepsilon  E\\\\E=\dfrac{10.2}{0.00068}\\E= 15000\ MPa\\E=15\ GPa

Therefore the young's modulus will be 15 GPa.

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An engine cylinder has a stroke of 320mm and bore 280MM. Calculate the mass of air contained in the cylinder if it is filled wit
belka [17]

Answer:

The mass of the air is 0.0243 kg.

Explanation:

Step1

Given:

Stroke of the cylinder is 320 mm.

Bore of the cylinder is 280 mm.

Pressure of the air is 101.3 kpa.

Temperature of the air is 13°C.

Step2

Calculation:

Stroke volume of the cylinder is calculated as follows:

V=\frac{\pi }{4}d^{2}L

V=\frac{\pi}{4}\times(\frac{280}{1000})^{2}\times(\frac{320}{1000})

V = 0.0197 m³.

Step3

Assume air an ideal gas with gas constant 287 j/kgK. Then apply ideal gas equation for mass of the air as follows:

PV=mRT

m=\frac{PV}{RT}

m=\frac{101.3\times 1000\times 0.0197}{287\times (13+273)}

m= 0.0243 kg.

Thus, the mass of the air is 0.0243 kg.

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