Answer:
B. G = 333 mS, B = j250 mS
Explanation:
 impedance of a circuit element is Z = (3 + j4) Ω
The general equation for impedance
 Z = (R + jX) Ω
where 
R = resistance in ohm
X = reactance
R = 3Ω  X = 4Ω
Conductance = 1/R while Susceptance = 1/X
Conductance = 1/3 = 0.333S
= 333 mS
Susceptance = 1/4 = 0.25S
= 250mS
The right option is B. G = 333 mS, B = j250 mS
 
        
             
        
        
        
Answer:
None of these 
Explanation:
There are different types of amplifiers, and each has different characteristics.
- Voltage amplifier needs high input and low output  resistance.
- Current amplifier needs Low Input and High Output  resistance.
- Trans-conductance amplifier Low Input and High Output resistance.
- Trans-Resistance amplifier requires High Input and Low output  resistance.
Therefore, the correct answer is "None of these "
 
        
             
        
        
        
Answer:
Local judges protected businessmen from paying property damages associated with factory construction and from workers seeking to unionize.
Explanation:
The Market Revolution is the name given to change in the economy that occurred in the 19th century. This drastic change led to various important changes in the United States and across the world. During this period, capitalism became more entrenched and society became, for the first time, predominantly capitalist. This gave businessmen great power, as they played an increasingly important role when it came to economic growth. The power that they had influenced society deeply, including legislation. Judges often protected businessmen from paying property damages that were associated with their business enterprises. Moreover, workers had few rights and protections, and judges prevented them from unionizing.
 
        
             
        
        
        
 A. 5 seconds :) Good luck!
        
             
        
        
        
Answer:
8.85 Ω
Explanation:
Resistance of a wire is:
R = ρL/A
where ρ is resistivity of the material,
L is the length of the wire,
and A is the cross sectional area.
For a round wire, A = πr² = ¼πd².
For aluminum, ρ is 2.65×10⁻⁸ Ωm, or 8.69×10⁻⁸ Ωft.
Given L = 500 ft and d = 0.03 in = 0.0025 ft:
R = (8.69×10⁻⁸ Ωft) (500 ft) / (¼π (0.0025 ft)²)
R = 8.85 Ω