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3 years ago

A rock is lifted by a machine to a height of 10m. If it has a mass of 22 kilograms

Physics

1 answer:

zmey [24]3 years ago

5 0

Answer:

2156J

Explanation:

Given parameters:

Height of lift = 10m

Mass = 22kg

Unknown:

Work done by the machine = ?

Solution:

Work done is the force applied to move a body through a certain distance.

So;

Work done = Force x distance

Here;

Work done = mass x acceleration due to gravity x height

Work done = 22 x 9.8 x 10 = 2156J

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If a bat hits a ball with a 1000-N force, what force does the ball exert on the bat?

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Same magnitude (1000N) and opposite direction
you may also answer -1000 N

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3 years ago

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Assume it takes 10 J to stretch a spring 10 cm beyond its natural length. Find the work required (in Joules) to stretch the spri

Lady bird [3.3K]

Answer:

W = 30 J

Explanation:

given,

Work done = 10 J

Stretch of spring, x = 0.1 m

We know,

dW = F .dx

we know, F = k x

$\int dW = \int_0^{0.1} k.x dx$

$W = \int_0^{0.1} k.x dx$

$W = k[\dfrac{x^2}{2}]_0^{0.1}$

$10 = k\dfrac{0.1^2}{2}$

k = 2000

now, calculating Work done by the spring when it stretched to 0.2 m from 0.1 m.

$W = \int_{0.1}^{0.2} 2000 x dx$

$W = 2000 [\dfrac{x^2}{2}]_{0.1}^{0.2} dx$

W = 1000 x 0.03

W = 30 J

Hence, work done is equal to 30 J.

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3 years ago

Tangential velocity 2. Parabolic pathway 3. Projectile 4. Centripetal acceleration 5. Centripetal force a. acceleration towards

Stels [109]

1. Tangential velocity:

e) the instantaneous velocity of a body moving in a circular path.

2. Parabolic pathway

c. a curved path followed by projectiles

3. Projectile

d) an object projected through space, traveling in two dimensions, that accelerates vertically due to gravity.

4. Centripetal acceleration

a) acceleration towards the center caused by the centripetal force

5. Centripetal force

b) a force which keeps a body moving with a uniform speed along a circular path and is directed along the radius towards the center

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3 years ago

Calculate the work done by a 50.0 N force on an object as it moves 9.00 m, if the force is oriented at an angle of 135° from the

aivan3 [116]

Answer:

Work done, W = -318.19 Joules

Explanation:

It is given that,

Force acting on the object, F = 50 N

Distance covered by the force, d = 9 m

Angle between the force and the distance traveled, $\theta=135^{\circ}$

The work done by an object is equal to the product of force and distance traveled. It is equal to the dot product of force and the distance. Mathematically, it is given by :

$W=Fd\ cos\theta$

$W=50\times 9\times \ cos(135)$

W = -318.19 Joules

So, the work done by the force is 318.19 Joules. The work is done in opposite to the direction of motion. Hence, this is the required solution.

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3 years ago

Which describes refraction? *

sergey [27]

Answer:

Refracted rays travel through a boundary into a new medium.

Explanation:

Refracted rays travel through a boundary into a new medium. is only true for refraction.

The angle of incidence is the same for angle of refraction, is not true for refraction. Refraction follows Snell's law, states that ratio of the sine of the angle of refraction and the sine of the angle of incidence is always constant and equivalent to the ratio of phase velocities of the two mediums it is passing through.

Refracted rays change direction and go back to the original medium is false for refraction however, it is true for reflection.

5 0

3 years ago