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dedylja [7]
3 years ago
14

The nth term of the sequence is n^2 + 20

Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0

Answer: 5 terms.

Step-by-step explanation:

We know that the n-th term of a sequence is:

Aₙ = n² + 20

Where n can be any natural number, then n ∈ {1, 2, 3, ...}

We want to find how many terms are smaller than 50.

Then we could find the first value of n such that Aₙ is equal or larger than 50.

Then we can solve:

Aₙ = n² + 20 = 50

then:

n² = 50 - 20 = 30

n = √30 = 5.48

This is not a natural number, so we need to round to the next one that is n = 6

This means that the first natural number n such that Aₙ is equal or larger than 50 is n = 6, then for the values:

n = 1, 2, 3, 4, 5

Aₙ is smaller than 50

This means that there are 5 terms of the sequence that are smaller than 50.

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padilas [110]

Answer:

Option (3)

Step-by-step explanation:

Area of a circle is given by the formula,

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Here, r = radius of the circle

Since, radius of the circular trampoline = 8 feet

Area of the cover required for the circular trampoline = π(8)²

                                                                                         = 64π square feet

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3 years ago
Which equation has a graph that goes through the points (4, -6) and (0, 6)?
Ugo [173]

Answer:

y = -3x + 6\\

Step-by-step explanation:

Find the gradient of the equation

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The equation will have the gradient -3x

Use the general equation of a line, and substitute the coordinates in to find the y-intercept.

y = x + c\\ y = -3x + c\\

(4, -6)

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(0, 6)

6 = -3(0) + c\\ 6 = -0 + c\\ c = 6

The equation of the line is

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4 0
3 years ago
A square has a perimeter of 52cm , what is the area ?
UNO [17]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The area is 169 square cm.

Find the value of each side (a square has 4 sides so divide by 4 ):

52/4 = 13

To find the area of a square, you only need 2 sides so multiply 2 sides:

13 x 13 = 139

Area = 139 square cm

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

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What is the unknown fraction?
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.................................................

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