All categories

1 year ago

Question 2 of 10

1 answer:

8 0

Scientists tell people which issues are the most important describes an important role scientists have in society.

In addition to advising policymakers and other stakeholders about the best and wisest steps to take toward a human-centered society, scientists have a crucial role to play in preventing unwise and dangerous decisions. This promotes scientific knowledge and strengthens cross-cultural relationships and collaborative research. Additionally, they shouldn't overlook the objective, perpetually unfinished nature of science. With the help of a transdisciplinary cross-talks method, we emphasize the significance of information transfer across all scientific disciplines.

Due to the specific ways in which they aid in understanding how the world functions, scientists are crucial to society. It is a mode of thinking that helps us organize our knowledge in order to comprehend how things operate on a deeper level.

Learn more about Scientists here

brainly.com/question/22249890

#SPJ9

You might be interested in

The half-life of cesium-137 is 30 years. Suppose we have a 180 mg sample. Find the mass that remains after t years. Let y(t) be

Stels [109]

Explanation:

1) Initial mass of the Cesium-137= $N_o$ = 180 mg

Mass of Cesium after time t = N

Formula used :

$N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

Half life of the cesium-137 = $t_{1/2}=30 years[p/tex]where,
[tex]N_o$ = initial mass of isotope

N = mass of the parent isotope left after the time, (t)

$t_{\frac{1}{2}}$ = half life of the isotope

$\lambda$ = rate constant

$N=N_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}$

Now put all the given values in this formula, we get

$N=180mg\times e^{-\frac{0.693}{30 years}\times t}$

Mass that remains after t years.

$N=180 mg\times e^{0.0231 year^{-1}\times t}$

Therefore, the parent isotope remain after one half life will be, 100 grams.

t = 70 years

$N_o=180 mg$

$t_{1/2}= 30 yeras$

$N=180mg\times e^{-\frac{0.693}{30 years}\times 70 years}$

N = 35.73 mg

35.73 mg of cesium-137 will remain after 70 years.

$N_o=180 mg$

$t_{1/2}= 30 yeras$

N = 1 mg

t = ?

$1 mg =180mg\times e^{-\frac{0.693}{30 years}\times t}$

$\frac{-30 year}{0.693}\times \ln \frac{1 mg}{180 mg}=t$

t = 224.80 years ≈ 225 years

After 225 years only 1 mg of cesium-137 will remain.

7 0

3 years ago

If 2 different gases have the same volumes but different masses, how will their densities compare?

olga_2 [115]

can i have brainiest

The two samples will have the same density because they are the same substance. The volume will have increased just enough to balance the greater mass. Key Concept- When substances have the same volumes but different masses, the substance having the greatest mass will be the most dense.

3 0

3 years ago

Read 2 more answers

What is a polyprotic buffer?

coldgirl [10]

Buffers - mixtures of conjugate acid and conjugate base at ±1 pH unit from pH = pKa. Resistant to changes in pH in response to small additions of H+ or OH-. ... Polyprotic acids - dissociation of each H+ can be treated separately if the pKa values are different

3 0

2 years ago

Find the value of 6 +<br>6 +<br>6 + 16 + vo

AVprozaik [17]

Answer:

Explanation:

the value is 6 because its an even number

7 0

2 years ago

Balance the equation for magnasuin and oxygen to yield magnasuimoxide

Minchanka [31]

Answer:

2Mg + O₂ → 2MgO

Explanation:

Chemical equation:

Mg + O₂ → MgO

Balanced chemical equation:

2Mg + O₂ → 2MgO

The balanced equation s given above and it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Steps to balanced the equation:

Step 1:

Mg + O₂ → MgO

Mg = 1 Mg = 1

O = 2 O = 1

Step 2:

2Mg + O₂ → MgO

Mg = 2 Mg = 1

O = 2 O = 1

Step 3:

2Mg + O₂ → 2MgO

Mg = 2 Mg = 2

O = 2 O = 2

6 0

3 years ago