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ankoles [38]
3 years ago
6

The first person to discover time​

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
5 0
The Egyptians when they created the sundial
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An object launched straight puwar from the ground level wiht an initional velocity of 32 feet per second.The formula H=32T-16T^2
Dima020 [189]

Answer:

2 secs after

Step-by-step explanation:

Given the height of the object modeled by the eqaution;

H(t) = 32T - 16T² where;

T is the time in seconds

The object hits the ground when h(t)= 0

Substitute H = 0 into the equation and get t as shown;

0 =  32T - 16T²

0-32T = -16T²

-32T = -16T²

32T = 16T²

32 = 16T

T = 32/16

T = 2secs

Hence the object hits the ground after 2 secs

6 0
3 years ago
Letters a, b, c, and d are angle measures.
DerKrebs [107]
D
b equals to 75 because they are diagonal, and the one diagonal to a equals 105 so that a and b form a line.
In order to prove f||g, we need to prove c=b, so c equals 75, d equals 105
7 0
2 years ago
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4 0
4 years ago
Identify the zeros of the function f(x) =2x^2 − 2x + 13 using the Quadratic Formula. SHOW WORK PLEASE!! I NEED HELP!!
babunello [35]

Answer:

x=\frac{1+5i} {2}   and  x=\frac{1-5i} {2}

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

f(x)=2x^{2} -2x+13  

Equate the function to zero

2x^{2} -2x+13=0  

so

a=2\\b=-2\\c=13

substitute in the formula

x=\frac{-(-2)\pm\sqrt{-2^{2}-4(2)(13)}} {2(2)}

x=\frac{2\pm\sqrt{-100}} {4}

Remember that

i=\sqrt{-1}

so

x=\frac{2\pm10i} {4}

Simplify

x=\frac{1\pm5i} {2}

therefore

x=\frac{1+5i} {2}   and  x=\frac{1-5i} {2}

7 0
3 years ago
A:b 1:5 a:c 2:1 how many times is b bigger than c ?
Ronch [10]

Answer:

b is 10 times greater

Step-by-step explanation:

If we multiply the first ratio by 2/2, we get 2/10. Since b=10 and c=1, b is 10 times greater.

3 0
3 years ago
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