Answer:
30.63 m
Explanation:
From the question given above, the following data were obtained:
Total time (T) spent by the ball in air = 5 s
Maximum height (h) =.?
Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:
Total time (T) spent by the ball in air = 5 s
Time (t) taken to reach the maximum height =.?
T = 2t
5 = 2t
Divide both side by 2
t = 5/2
t = 2.5 s
Thus, the time (t) taken to reach the maximum height is 2.5 s
Finally, we shall determine the maximum height reached by the ball as follow:
Time (t) taken to reach the maximum height = 2.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =.?
h = ½gt²
h = ½ × 9.8 × 2.5²
h = 4.9 × 6.25
h = 30.625 ≈ 30.63 m
Therefore, the maximum height reached by the cannon ball is 30.63 m
Answer:
I= 20 i {N.s}
Explanation:
In order to obtain the impulse on the 2 kg ball, you have to apply the equation of Impulse:
I=FΔt
Where I is the impulse vector, F is the net force and Δt is the interval of time when the force is applied.
In this case:
Δt=0.01 s
F= 2000 i N
where i is the unit vector in the x direction.
Replacing the values in the formula:
I=(2000)(0.01)i
Therefore:
I= 20 i {N.s}
Light waves travel in straight lines when they are travelling in a uniform medium. This is because the waves are travelling at the same speed.
The power source voltage remains the same in a parallel circuit,
And we'll have equal current in both lines
<h3>Kirchhoff's junction rule</h3>
Generally, Kirchhoff's junction rule states that when there is current flow at any junction of a circuit, the total sum of this current rushing into the junction amount to the same amount of current out of the Node.
Therefore, when the parallel circuit has two branches
i=i1+12
Since we have an equal resistor therefore we'll have equal current in both lines i.e i1=i2
And Voltage remains the same in a parallel circuit
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Dont where socks or stand on carpet while working on a computer, also dont set components on carpet.