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ki77a [65]
2 years ago
10

Two students conduct the same experiment, but they get different results. What should the students do next?A.The students should

check their procedure and tools for sources of error. B.Both students should throw out their data and start over. C.The students should compare data with other students and then use the data from the student who was closest to the rest of the class. D.The students should find the average of each data set and each report the average data.
Chemistry
2 answers:
blsea [12.9K]2 years ago
4 0

Answer:

A.The students should check their procedure and tools for sources of error.

Explanation:

alexandr1967 [171]2 years ago
3 0

Answer:

I think it A

Explanation:

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For the following reaction, 142 grams of silver nitrate are allowed to react with 22.3 grams of copper . silver nitrate(aq) copp
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Answer:

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3 years ago
A coke has a ph of 3.5. this means that it has an excess of _______ ions and would be called a(n) _____.
Anuta_ua [19.1K]
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3 0
3 years ago
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Calculate the atomic mass of silver if 13 out of 25 atoms are silver-107 and 12 out of 25 are silver-109
nekit [7.7K]

From,

RAM=element×its relative abudance/total abudance

=((107×13)+(12×109))/25

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3 0
3 years ago
the element carbon has two common isotopes: C-12 (12 U) AND C-13 (13.003355 U). IF THE AVERAGE ATOMIC MASS OF CARBON IS 12.0107
oksian1 [2.3K]

Answer:

The percent isotopic abundance of C- 12 is 98.93 %

The percent isotopic abundance of C- 13 is 1.07 %

Explanation:

we know there are two naturally occurring isotopes of carbon, C-12 (12u)  and C-13 (13.003355)

First of all we will set the fraction for both isotopes

X for the isotopes having mass 13.003355

1-x for isotopes having mass 12

The average atomic mass of carbon is 12.0107

we will use the following equation,

13.003355x + 12 (1-x) = 12.0107

13.003355x + 12 - 12x = 12.0107

13.003355x- 12x = 12.0107 -12

1.003355x = 0.0107

x= 0.0107/1.003355

x= 0.0107

0.0107 × 100 = 1.07 %

1.07 % is abundance of C-13 because we solve the fraction x.

now we will calculate the abundance of C-12.

(1-x)

1-0.0107 =0.9893

0.9893 × 100= 98.93 %

98.93 % for C-12.

7 0
3 years ago
Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. express the nu
bagirrra123 [75]
<span>To calculate the number of moles of aluminum, sulfur, and oxygen atoms in 4.00 moles of aluminum sulfate, al2(so4)3. We will simply inspect the "number" of aluminum, sulfur, and oxygen atoms available per one mole of the compound. Here we have Al2(SO4)3, which means that for every mole of aluminum sulfate, there are 2 moles of aluminum, 3 (1 times 3) moles of sulfur, and 12 (4x3) moles of oxygen. Since we have four moles of Al2(SO4)3 given, we simply multiply 4 times the moles present per 1 mole of the compound. So we have 4x2 = 8 moles of Al, 4x3 = 12 moles of sulfur, and 4x12 = 48 moles of oxygen.

So the answer is:
8,12,48


</span>
3 0
3 years ago
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