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ki77a [65]
2 years ago
10

Two students conduct the same experiment, but they get different results. What should the students do next?A.The students should

check their procedure and tools for sources of error. B.Both students should throw out their data and start over. C.The students should compare data with other students and then use the data from the student who was closest to the rest of the class. D.The students should find the average of each data set and each report the average data.
Chemistry
2 answers:
blsea [12.9K]2 years ago
4 0

Answer:

A.The students should check their procedure and tools for sources of error.

Explanation:

alexandr1967 [171]2 years ago
3 0

Answer:

I think it A

Explanation:

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170/28 > 130/28
3 0
2 years ago
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he number-average molecular weight of a polypropylene is 1,000,000 g/mol. Compute the degree of polymerization.
m_a_m_a [10]

Answer:

The answer is "23765.4"

Explanation:

Motor weight average number (\bar{M_n}) = 1000000 \frac{g}{mol}

Poly condensation degree dependent on the average number of molecular weights is as follows:

DP_n = \frac{\text{Mol.Wt Number Medium}}{\text{Monomer Unit Mol.Wt}}

All monomer module, in this case, is propylene  

Sunrise. Unit Wt = Mol. Propylene weight

                           = \ Mol. \ Wt \ of \ C_3H_6\\\\= 3 \times 12.01 +6 \times 1.008 \ \ \frac{g}{mol}\\\\= 42.078 \frac{g}{mol}\\\\

DP_n = \frac{1000000}{42.078}\\\\

    =23765.4

8 0
2 years ago
Consider a solution prepared by mixing the following:50.0 mL of 0.100 M Na3PO4100.0 mL of 0.0500 M KOH200.0 mL of 0.0750 M HCl50
Juliette [100K]

Answer:

you must add 50 mL

Explanation:

Hi

KOH is a strong base and by adding 100mL 0.05M you will have an amount of 5 millimol.

NaCN is a base and by adding 50 mL 0,150 M you will have an amount of 7,5 mmol.

HCl is a acid and by adding 200 mL 0,075 M you will have an amount of 15 mmol.

The acid reacts with the bases leaving 2.5 mmol unreacted.

Na3PO4 is a base and by adding 50 mL 0,1 M you will have an amount of 5 mmol.

The 2.5 mmol of acid react with the base PO4 ^ -3 forming a regulatory solution of PO4 ^ -3 and HPO4 ^ -2 of pKa 2.12

5 mmol of acid (HNO3) must be added to obtain a regulatory solution formed by the same amount of HPO4 ^ -2 (2.5 mmol) and H2PO4 ^ -1 (2.5 mmol) with pKa 7.21

Considering a quantity of 5 mmol of HNO3 of concentration 0.1 M, 50 mL must be added.

To calculate the pH of the regulatory solution you should consider pH = pKa × Ca / Cb pH = 7.21 × 2.5 / 2.5 = 7.21 Being in the same solution the volume is the same and can be simplified to achieve a faster calculation.

successes with your homework

5 0
3 years ago
Planck's constant, h, is 6.626 x 10-34 Js. The speed of light in a vacuum, c, is 3.00 x 108 m/s. Calculate the energy of ultravi
igomit [66]

Given the Planck's constant and the speed of light, the energy of the ultraviolet light with a frequency of 9.58×10¹⁴ Hz is 6.35×10¯¹⁹ J (Option C)

<h3>Data obtained from the question </h3>
  • Planck's constant (h) = 6.626×10¯³⁴ Js
  • Speed of light (v) = 3×10⁸ m/s
  • Frequency (f) = 9.58×10¹⁴ Hz
  • Energy (E) =?

<h3>How to determine the energy </h3>

The energy of the ultraviolet light can be obtained as follow:

E = hf

E = 6.626×10¯³⁴ × 9.58×10¹⁴

E = 6.35×10¯¹⁹ J

Learn more about energy:

brainly.com/question/10703928

8 0
2 years ago
6th grade science plz help Major grade Need help with 4,5, and 6
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4=population, 5 and 6 are ecosystem
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