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ratelena [41]
3 years ago
11

HURRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRY

Physics
2 answers:
vivado [14]3 years ago
5 0
The answer is D. Atomic particles can be very dangerous to observe directly 
hoped this helped
Feel free to ask anymore questions here at brainly.com
ivann1987 [24]3 years ago
5 0

c- atomic particles are too small to be observed directly

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A 160-N child sits on a light swing and is pulled back and held with a horizontal force of 100 N. The magnitude of the tension f
guajiro [1.7K]

Answer:

T = 190 N

Explanation:

When child is sitting on the swing then the weight of the child is vertically downwards

So it is

F_g = 160 N

now a force of 100 N is acting on the swing in horizontal direction

so it is given as

F_x = 100 N

now the net force is resultant force due to gravity and horizontal force

so it is given as

T = \sqrt{F_x^2 + F_g^2}

T = \sqrt{100^2 + 160^2}

T = 190 N

3 0
2 years ago
The transfer of heat by the movement of a fluid is called:
rusak2 [61]

Answer: C

Explanation:

Convective heat transfer, or convection, is the transfer of heat from one place to another by the movement of fluids, a process that is essentially the transfer of heat via mass transfer.

3 0
3 years ago
A train, traveling at a constant speed of 25.8 m/s, comes to an incline with a constant slope. While going up the incline, the t
zhannawk [14.2K]

The final velocity of the train after 8.3 s on the incline will be 12.022 m/s.

Answer:

Explanation:

So in this problem, the initial speed of the train is at 25.8 m/s before it comes to incline with constant slope. So the acceleration or the rate of change in velocity while moving on the incline is given as 1.66 m/s². So the final velocity need to be found after a time period of 8.3 s. According to the first equation of motion, v = u +at.

So we know the values for parameters u,a and t. Since, the train slows down on the slope, so the acceleration value will have negative sign with the magnitude of acceleration. Then

v = 25.8 + (-1.66×8.3)

v =12.022 m/s.

So the final velocity of the train after 8.3 s on the incline will be 12.022 m/s.

8 0
3 years ago
How much work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s?
soldi70 [24.7K]

Answer:

The correct option is (b).

Explanation:

We need to find the work done to increase the speed of a 1 kg toy car by 5 m/s.

We know that, the work done is equal to the kinetic energy of an object i.e.

W=\Delta K\\\\W=\dfrac{1}{2}mv^2\\\\W=\dfrac{1}{2}\times 1\times 5^2\\W=12.5\ J

So, 12.5 J of work is done to increase the speed of a 1.0 kg toy car by 5.0 m/s.

6 0
3 years ago
What is the total surface charge qint on the interior surface of the conductor (i.e., on the wall of the cavity)
RSB [31]

Answer: hello your question is incomplete below is the missing part

A spherical cavity is hollowed out of the interior of a neutral conducting sphere. At the center of the cavity is a point charge, of positive charge q.

answer:

- q

Explanation:

Since the spherical cavity was carved out of a neutral conducting sphere hence the electric field inside this conductor = zero

given that there is a point charge +q at the center of the spherical cavity hence for the electric field inside the conductor to be = zero the total surface charge qint on the wall of the cavity will be -q

6 0
3 years ago
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