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butalik [34]
3 years ago
5

Give 3 examples of solutions, suspensions and colloids..

Chemistry
2 answers:
Soloha48 [4]3 years ago
8 0

SOLUTIONS:

  • Tap Water
  • Air
  • Sterling Silver

SUSPENSIONS:

  • Flour in water
  • the mixture of chalk and water
  • muddy water

COLLOIDS:\\

  • fog
  • smog
  • toothpaste

hope it helps you

Vlad [161]3 years ago
5 0
  • <u>Some examples of solutions</u><u>"</u><u>:</u><u>"</u><u> are salt water, rubbing alcohol, and sugar dissolved in water.</u>

  • <u>examples of suspensions are </u><u>muddy water milk of magnesia </u><u>Slaked lime for whitewashing.</u>

  • <u>examples of colloids are </u><u>whipped cream, mayonnaise, milk, </u>
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5 0
3 years ago
Which of the following ionic compounds would be considered insoluble in water?
lubasha [3.4K]

Answer:

C. CaCrO4

Explanation:

(A. and D.) have alkaline metals Cs and Na, (B.) has NH4 -ion. Their salts are always soluble.

3 0
4 years ago
water at 400 kPa and 60°C while the other part is evacuated. The partition is now removed, and the water expands to fill the ent
kaheart [24]

Answer:

0.4912 kJ/K

Explanation:

Using steam table, the properties of water at stage 1 can be determined:

P_{1} = 400 kPa

T_{1} = 60°C

Therefore, from steam table:

specific volume v_{1}  = 0.001017 m^{3}/kg

entropy  s_{1}  = 0.8313 kJ/kg*K

Calculating the specific volume of water after the partition is removed, since the mass is constant and volume of water is doubled:

v_{2} = 2*0.001017 = 0.002034 m^{3}/kg

Final pressure of water in the tank = P_2} = 40 kPa

dryness factor after removing the partition

x = \frac{0.002034 - 0.001026}{3.993 - 0.001026} = 2.524*10^{-4} kg/vapor

Therefore:

s_{2} = s_{f2} + x*s_{fg2}  = 1.0261 + (2.524*10^{-4}*6.643) = 1.02778 kJ/kg*K

Thus, the entropy change is:

Δs = m*(s_{2}-s_{1}) = 2.5*(1.02778 - 0.8313) = 0.4912 kJ/K

Therefore, the entropy change of water is 0.4912 kJ/K

6 0
4 years ago
How much heat is required to convert 12. 0 g of ice at -10. 0 ºc to steam at 100. 0 ºc?
nordsb [41]

Main Answer:

Given data:

Mass of ice m = 12 grams = 12/1000 = 0.012 kg

Specific heat  s = 4.18 KJ/ gm-1 C-1

Change in temperature t = t2 - t1

t = 100 - (-10)

t = 100 + 10 = 110C

Heat required Q = m x s x t

Q = 0.012 x 4.18 x 110

Q = 5.5176 KJ

Explanation:

What is heat?

Heat is defined as one of the forms of energy. It is a kinetic energy which can be transferred from one object to another object or medium. It cannot be destroyed or created. The units of heat is Joules in SI system and calories in CGS system.  

To know more about heat, please visit:

brainly.com/question/13439286

#SPJ4

8 0
2 years ago
Salt mixed in water is an example of a___
Natasha2012 [34]
The answer to this is a solution
3 0
3 years ago
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