Question

when 0.15 moles of sodium reacts with 0.30 moles of oxygen what is the moles of the product formed when one reagents is used in excess

Answer 1

Answer:

0.075 moles of product formed.

Explanation:

Given data:

Number of moles of oxygen = 0.30 mol

Number of moles of oxygen = 0.15 mol

Number of moles of product formed = ?

Solution:

Chemical equation:

4Na + O₂       →    2Na₂O

Now we will compare the moles of Na₂O with oxygen and sodium.

                Na           :           Na₂O

                  4            :              2

                  0.15       :          2/4×0.15 = 0.075 mol

                O₂           :           Na₂O

                  1            :              2

                  0.30       :          2/1×0.30 = 0.6 mol

Less number of moles of Na₂O are produced by sodium thus it will limit the yield of  Na₂O and act as limiting reactant while oxygen is in excess.