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Xelga [282]
3 years ago
12

Help ASAP please !!!!!

Mathematics
1 answer:
Dafna1 [17]3 years ago
4 0

Answer:

Here am i

Step-by-step explanation:

I can help u with any question

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Hello! Please help me with this. I'm very desperate lol. Its 16. Ill give brainliest
Paladinen [302]

Answer:

You showed the right work and got the right answer!

x = 6

Step-by-step explanation:

Since B is in the middle of A and C, AB + BC = AC

So,

2x - 11 + 8 = x + 3

x - 3 = 3

x = 6

7 0
1 year ago
In a sample of eight whitefish caught in Yellowknife Bay, the mean arsenic concentration in the liver was 0.32 mg/kg, with a sta
Advocard [28]

Answer:

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 8 - 1 = 7

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.3246

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.3646\frac{0.06}{\sqrt{8}} = 0.0502

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.32 - 0.0502 = 0.2698 mg/kg

The upper end of the interval is the sample mean added to M. So it is 0.32 + 0.0502 = 0.3702 mg/kg

The 95% confidence interval for the concentration in whitefish found in Yellowknife Bay is (0.2698 mg/kg, 0.3702 mg/kg).

8 0
2 years ago
The value of x and y
kompoz [17]

Answer:

?????

Step-by-step explanation:

3 0
3 years ago
Pls help me with this question and explain how you got the answer!!!!!
Luba_88 [7]

Answer:

-87

Step-by-step explanation:

So, first to find <em>x</em> you need to subtract 121 from 180. You do this because both the angle which measures 121 degrees and <em>x</em> lie on the same line, and since a line has an angle measure of 180, you do 180-121 to find <em>x</em>. The same thing can be done for <em>y</em>. Since the angle measure of 34 degrees and y lie on the same line you can calculate 180-34 to get <em>y. </em>So, let's do that.

180-121=x

59=x

180-34=y

146=y

Once you've done that you can easily subtract the two and get your answer.

x-y

substitute the answer for the variables and get

59-146

and then your answer is

-87

4 0
3 years ago
Premier Bank is planning to have a new building constructed. They would like the length of the building to be 40 feet longer tha
MaRussiya [10]

Let L, W, F, H, P represent, respectively, the length, width, number of floors, height, and perimeter of the building. Here are some equations that model the given information.

  • L = W + 40
  • H = 12×F
  • foundation cost = 10×L×W
  • cost of floors = 35000×F
  • total cost = foundation cost + cost of floors
  • total cost = 1,180,000
  • P = 2×(L+W)
  • P = 3×H

We can rewrite these into a system of equations involving L, W, F.

Let's look first at the relation between the perimeter and height. The two versions of perimeter are equal to each other, so we have (after substituting for H) ...

... 3H = 2(L+W)

... 3(12F) = 2((W +40) +W) . . . . substitute for H and L

... 36F = 4W +80 . . . . . . . . . . . simplify

... 9F = W +20 . . . . . . . . . . . . . divide by 4

Now, we can look at the cost equations.

... 1180000 = 35000F + 10W(W+40) . . . . . substitute for the various cost terms and for L

... 118000 = 3500F +W² +40W . . . . . . . . . divide by 10

The two simplified equations in W and F are ...

  • 9F = W +20
  • 3500F = 118000 -40W -W²

You can solve the first for F and substitute for F in the second. Then you have a quadratic equation in W that can be solved by the usual methods. (Likely, the quadratic formula would be the best choice.) Here, we have elected to let a graphing calculator show the two solutions. One solution has negative dimensions, so is clearly infeasible.

There is one (nearly feasible) solution:

... W ≈ 180.788

... F ≈ 22.31

There is no combination of floor dimensions and integral numbers of floors that will match <em>all</em> of the problem requirements.

_____

A solution that comes about as close as possible is ...

  • length = 221 ft
  • width = 181 ft
  • perimeter = 804 ft
  • # of floors = 22
  • height = 264 ft . . . . . (3×height = 792 ft vs. 804 ft)
  • cost = $1,170,010 . . . (vs. 1,180,000)

4 0
3 years ago
Read 2 more answers
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