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Explanation:

8 0

3 years ago

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Write the electron configuration for the elements whose atomic numbers are the following:

andreev551 [17]

Answer:

3= Lithium (Li) = [He] 2s1

6= Carbon (C) = [He] 2s2 2p2

8=Oxygen (O)= [He] 2s2 2p4

13=Aluminium (Al)= [Ne] 3s2 3p1

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6 0

2 years ago

Which of the following are the types of RNA?

Andrew [12]

Answer:

Explanation:

Of the numerous sorts of RNA, the three most well-known and most commonly examined are delivery person RNA (mRNA), exchange RNA (tRNA), and ribosomal RNA (rRNA), which are show in all living beings. These and other sorts of RNAs essentially carry out biochemical responses, comparative to proteins.

5 0

3 years ago

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If 20 grams of Zinc phosphate reacts with excess hydrochloric acid and produces 18 grams of Zinc chloride what is the percent yi

fenix001 [56]

Answer:

$Y=85\%$

Explanation:

Hello!

In this case, since we know the balanced chemical reaction, we are first able to realize there is a 1:3 mole ratio between zinc phosphate and zinc chloride; it means that we can first compute the moles of the desired product via stoichiometry:

$n_{ZnCl_2}=20gZn_3(PO_4)_2*\frac{1molZn_3(PO_4)_2}{386.11gZn_3(PO_4)_2}*\frac{3molZnCl_2}{1molZn_3(PO_4)_2}=0.16gZnCl_2$

Next, since those moles are associated with the theoretical yield of zinc chloride, we obtain the corresponding mass:

$m_{ZnCl_2}^{theoretical}=0.16molZnCl_2*\frac{136.29gZnCl_2}{1molZnCl_2} =21gZnCl_2$

Finally, we compute the percent yield by diving the actual yield (18 g) by the theoretical yield:

$Y=\frac{18g}{21g}*100\%\\\\Y=85\%$

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4 0

3 years ago