Answer:
<621, 0 , 0>
Explanation:
given,
mass of the car ,m = 1425 Kg
location of car = < 266, 0, 0 > m
momentum of the car = < 46000, 0, 0 > kg.m/s
M v_x = 46000
1425 x v_x = 46000
v_x = 32.28 m/s
v_y = 0 m/s
v_z = 0 m/s
Location of the car after 11 s
x = v_x t + 266
x = 32.28 x 11 + 266
x = 621 m
hence, the location of car after 11 s is equal to <621, 0 , 0>
To develop the problem, we require the values concerning the conservation of momentum, specifically as given for collisions.
By definition the conservation of momentum tells us that,
To find the speed at which the arrow impacts the apple we turn to the equation of time, in which,
The linear velocity of an object is given by
Replacing the equation of time we have to,
Velocity two is neglected since there is no velocity of said target before the collision, thus,
Clearing for m_2
(1) First compute the linear speed of the mass. If it completes 1 revolution in 0.5 seconds, then the mass traverses a distance of 2<em>π</em> (1.0 m) ≈ 2<em>π</em> m (the circumference of the circular path), so that its speed is
<em>v</em> = (1/0.5 rev/s) • (2<em>π</em> m/rev) = 4<em>π</em> m/s ≈ 12.57 m/s
Then the centripetal acceleration <em>a</em> is
<em>a</em> = <em>v</em>² / (1.0 m) = 16<em>π</em>² m/s² ≈ 160 m/s²
(where <em>r</em> is the path's radius).
(2) By Newton's second law, the tension in the string is <em>T</em> such that
<em>T</em> = (0.50 kg) <em>a</em> = 8<em>π</em>² N ≈ 79 N
Answer:
Negative z-direction.
Explanation:
We need to determine the direction of the magnetic force. Since the velocity of the proton is in the positive x direction, and the magnetic field is in the positive y direction, we know by the vectorial formula 
(or, alternatively, with the <em>left hand rule</em>) that the magnetic force points in the positive z-direction (also taking into account that <u>the charge is positive</u>), so the electric field should be in the negative z-direction to balance it.
Answer:
a) 3.0×10⁸ m
b) 0 m
Explanation:
Displacement is the distance from the starting position to the final position.
a) In half a year, the Earth travels from one point on the circle to the point on the exact opposite side of the circle (from 0° to 180°). The distance between the points is the diameter of the circle.
x = 2r
x = 2 (1.5×10⁸ m)
x = 3.0×10⁸ m
b) In a full year, the Earth travels one full revolution, so it ends up back where it started. The displacement is therefore 0 m.
