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SpyIntel [72]
4 years ago
6

What's are the factors of 1078

Mathematics
2 answers:
soldi70 [24.7K]4 years ago
5 0
The factors of 1078 are 1, 2, 7, 11, 14, 22, 49, 77, 98, 154, 539, and 1078. 
Vikentia [17]4 years ago
3 0
1, 2, 7, 11, 14, 22, 49, 77, 98, 154, 549, and 1078
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Jennifer is shopping with her mother. They pay $2 per pound of tomatoes.
elena-14-01-66 [18.8K]

Answer:

The constant of proportionality is 2

The equation is y=2x

Step-by-step explanation:

The unit price or unit rate is $2

Let y represent the price of tomatoes, then the price of x tomatoes is

y=2x dollars.

This represents a direct variation.

This equation is of the form y=kx, where k=2 is the constant of proportionality.

4 0
3 years ago
If ΔABC ΔDEC, what is m∠D? A. 40° B. 150° C. 60° D. 80°
Nina [5.8K]
I think that the best answer here would be that A = 40 degrees. 
6 0
3 years ago
X^2=1/4 please help me
skelet666 [1.2K]
X² = 1/4 ⇒√⇒ x₁ = 1/2, x₂ = -1/2
5 0
3 years ago
Read 2 more answers
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

7 0
3 years ago
The sum of 3 consecutive number multiples of 6 is 162 find thesse numbers
MAXImum [283]

let the numbers are x , x+1 ,x+2

∴ 6 [ x + (x+1) +(x+2) ] = 162

∴ x + (x+1) + (x+2) = 162/6 = 27

∴3x + 3 = 27

∴ 3x = 27 - 3 = 24

∴ x = 24/3 = 8

<u>So, the numbers are 8 , 9 , 10</u>

7 0
3 years ago
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