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harina [27]
2 years ago
13

30 mL of 0.6 M HCl solution is neutralized with 90 mL NaOH solution. What is the concentration of the base? Show all work Please

:).
Chemistry
1 answer:
skad [1K]2 years ago
3 0

From

<em>n</em><em>a</em><em>=</em><em>1</em>

<em>n</em><em>b</em><em>=</em><em>1</em>

<em>V</em><em>a</em><em>=</em><em>3</em><em>0</em><em>m</em><em>l</em><em>s</em>

<em>V</em><em>b</em><em>=</em><em>9</em><em>0</em><em>m</em><em>l</em><em>s</em>

<em>M</em><em>a</em><em>=</em><em>0</em><em>.</em><em>6</em><em>M</em>

<em>M</em><em>b</em><em>=</em><em>?</em>

<em>f</em><em>r</em><em>o</em><em>m</em>

<em>Mb</em><em>=</em><em><u>M</u></em><em><u>a</u></em><em><u>×</u></em><em><u>V</u></em><em><u>a</u></em><em><u>×</u></em><em><u>n</u></em><em><u>b</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>V</em><em>b</em><em>×</em><em>n</em><em>a</em>

<em>M</em><em>b</em><em>=</em><em><u>0</u></em><em><u>.</u></em><em><u>6</u></em><em><u>×</u></em><em><u>3</u></em><em><u>0</u></em><em><u>×</u></em><em><u>1</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>9</em><em>0</em><em>×</em><em>1</em>

<em>m</em><em>b</em><em>=</em><em><u>1</u></em><em><u>8</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>9</em><em>0</em>

<em>M</em><em>b</em><em>=</em><em>0</em><em>.</em><em>2</em><em>M</em>

<em>NaOH</em><em>=</em><em>4</em><em>0</em>

<em>F</em><em>r</em><em>o</em><em>m</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>m</em><em>o</em><em>l</em><em>a</em><em>r</em><em>i</em><em>t</em><em>y</em><em>×</em><em>m</em><em>r</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>0</em><em>.</em><em>2</em><em>×</em><em>4</em><em>0</em>

<em>c</em><em>o</em><em>n</em><em>c</em><em>=</em><em>8</em><em>g</em><em>/</em><em>m</em><em>o</em><em>l</em>

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Answer:

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Explanation:

We have the  trans 1,2 - dimethylcyclohexane. With the wedge/dash structure we could not figure is this form is stable (If we do a comparison with the cis structure). But when we do a chair structure and ring flipped structure, this is easier to look.

The picture attached shows the structures, they are labeled as 1, 2 and 3, according to this problem.

In the chair structure, according to the picture below, you can see that both methyls are heading in the axial positions of the ring (One facing upward and the other downward). This is pretty stable, however, when the methyls are in those positions, the methyl position 1, can undergoes an 1,3 diaxial interactions with the hydrogens atoms (They are not drawn, but still are there), so this interaction makes this structure a little less stable that it can be.

On the other side, the ring flipped structure, we can see that both methyls are in the equatorials positions of the ring, and in these positions, it can avoid the 1,4 diaxial interactions with the hydrogens atoms, making this structure the most stable structure.

Hope this helps

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From   balanced equation above  the coefficient   for  H2  is  2  since  the number in  front of  H2  is 2



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