Answer:
y^2 +7y-30
Step-by-step explanation:
Step 1: Use FOIL
y·y = y^2
y· 10= 10y
-3·y= -3y
-3·10= -30
Step 2: <em>combine like terms</em>
y^2+ 10y-3y-30
7^2+ 7y-30
and thats all :)
hope this helped
The answer would be about 0.111
The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
Answer: D. between 4.79 and 4.8
Step-by-step explanation:
The square root of 23 (√23) is 4.79583152331. We can obviously eliminate A and B. C and D is left. C is wrong because if we approximate the square root of 23, which is 4.79583152331, we get 4.79. 4.79 > 4.78, so it can't be C. Hope this helps :)
Hi
(6x-5) (2x-1) = 12x²-6x-10x+5 = 12x²-16x +5
