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ruslelena [56]
3 years ago
6

What is Newton's 2nd law of motion? * Your answer

Physics
2 answers:
Novay_Z [31]3 years ago
4 0
Acceleration of an object is depended upon the net force acting open the object and the mass of the object
Andrei [34K]3 years ago
3 0

Answer:

Newton's second law describes the affect of net force and mass upon the acceleration of an object.

F = force

m = mass of an object

a = acceleration

Explanation:

f=m.a

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Consider a large truck and a small car driving up a straight steep hill. The truck is moving at 60 miles per hour and the car at
Oksana_A [137]

Answer:

The correct answer is option A.

Explanation:

Force is defined as push or pull on an object with mass due to which change velocity occurs (acceleration).

Force=Mass\times Acceleration

F=ma

a=\frac{dv}{dt}[tex][tex]m\times \frac{dv}{dt}[tex]We are given with large truck and small car at constant speed, which means that acceleration zero.[tex]a=\frac{dv}{dt}=0 if ,v = constant

Net force on the vehilce

F = Normal  - Weight

0 = N = W

N = W

So, the force experienced by the object will be due to its mass, and higher the mass more will be the experienced by an object.So, large truck will experience larger net force.

7 0
3 years ago
A wooden rod of negligible mass and length 84.0 cm is pivoted about a horizontal axis through its center. A white rat with mass
Mandarinka [93]

Answer:

v = 2.029 m/s

Explanation:

Given

L = 84.0 cm   ⇒  R = 0.5*L = 0.5*84 cm = 42 cm = 0.42 m

m₁ = 0.600 kg

m₂ = 0.200 kg

g = 9.8 m/s²

u₁ = u₂ = 0 m/s

v₁ = ?

v₂ = ?

Due to gravity, the bar oscillates and becomes vertical. The mass that occupies the lower position is the one with the highest torque. The one that reduces the potential energy (the system tends to the position of minimum energy). This is achieved if the mass that goes down is 0.6kg (that goes down 42cm) and the one that goes up is 0.2kg (goes up 42cm).

In this system mechanical energy is conserved, so we can match its value in the horizontal position with the one in the vertical.

then

Ei = Ki + Ui = 0.5*(m₁+m₂)*(0)² + (m₁+m₂)*9.8*(0) = 0 J

Ef = Kf + Uf

⇒ Kf = 0.5*(m₁+m₂)*v² = 0.5*(0.6+0.2)*v² = 0.4*v²

⇒ Uf = m₁*g*h₁ + m₂*g*h₂ = 0.6*9.8*(-0.42) + 0.2*9.8*0.42 = - 1.6464

⇒ Ef = Kf + Uf = 0.4*v² - 1.6464

Since

0 = 0.4*v² - 1.6464  ⇒  v = 2.029 m/s

v is the same value due to the wooden rod is pivoted about a horizontal axis through its center and the masses are on opposite ends.

v₁ = v₂ = v    ⇒  ω₁*R₁ = ω₂*R₂  ⇒ ω₁*R = ω₂*R  ⇒ ω₁ = ω₂ = ω

⇒ v = ω*R

5 0
3 years ago
A 2.4 mm -diameter copper wire carries a 37 A current (uniform across its cross section). Determine the magnetic field at the su
cluponka [151]

Answer:

Explanation:

We shall apply Ampere's circuital law to find out magnetic field . It is given as follows.

∫B.dl = μ₀ I , B is magnetic field , I is current ,  μ₀ is permeability .

Radius of the wire r = 1.2 x 10⁻³ m

magnetic field B will be circular in shape around the wire. If B is uniform

∫B.dl = B x 2πr  

B x 2πr  = μ₀ I

B = μ₀ I / 2πr

= 4π x 10⁻⁷ x 37 /2πx1.2 x 10⁻³

= 10⁻⁷ x 2x37 / 1.2 x 10⁻³

= 61.67 x 10⁻⁴ T

= 62  x 10⁻⁴ T

7 0
3 years ago
2225.6 grams =________ ft
AnnyKZ [126]

71606.562467

Is the complete answer

6 0
3 years ago
A car with a velocity of 6.4 m/s, forward, accelerates to a velocity of 10.6 m/s, forward, in 16 s. What is the card acceleratio
tatuchka [14]

Answer:

acceleration = 0.2625 m/s²

Explanation:

   acceleration = ( final velocity - initial velocity ) / time

Here the final velocity is  10.6 m/s and initial velocity is 6.4 m/s and time is 16 s.

using the equation:

acceleration =  ( 10.6 - 6.4 ) / 16

                     = 0.2625 m/s²

6 0
2 years ago
Read 2 more answers
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