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Katena32 [7]
3 years ago
12

Two lumps of clay having equal masses and speeds, but traveling in opposite directions, collide and stick together. Part A Which

of the following statements about this system of lumps must be true?
Physics
1 answer:
Tom [10]3 years ago
8 0

Answer:

Explanation:

mass of clay = m

velocity is u

By use of conservation of momentum

m x u - m x u = (m + m) x v

v = 0

So, they stick together and comes to rest.

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Answer:

(a) 2400N

(b) different

Explanation:

2.5 milliseconds = 0.0025 seconds

a) The momentum of the moving arm-hand of 1.5 kg and at 4m/s speed is the product of the mass and the speed

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After the slap, the arm-hand comes to rest, making the change in momentum of 6 - 0 = 6 kgm/s. This change in momentum is due to the impulse generated by the force within t = 0.0025 seconds.

So the average force is:

F = \frac{\Delta p}{\Delta t} = \frac{6}{0.0025} = 2400 N

b) If there are 2 hands clapping together at same speed and mass, their total momentum must be double of that. This makes the average force 2 times as before.

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