Compared to the charge of a proton, the charge of all electron has
2 answers:
The charge of a proton and the charge of all electron has<u><em> (4) the same magnitude and the opposite sign</em></u>
<h3>Further explanation</h3>Inside the atom consists of a nucleus containing 3 basic particles namely protons and neutrons, while electrons circulate the nucleus on a particular path so that electrons are not attracted to the nucleus.
The charge of these three atomic particles is based on the Rutherford experiment. Rutherford experimented with firing alpha rays on a thin gold plate. From this experiment it was found that:
- 1. Most alpha rays are passed through the gold plate, so it is concluded that most of the space in the atom has empty space
- 2. A small number of alpha particles deflected shows there are positively charged particles inside the atom
(at this time these particles are called protons located in the atomic nucleus)
From here comes the Rutherford atomic model which states that atoms consist of positively charged particles (protons) and negatively charged electrons around the nucleus.
<em>The charge of 1 proton is equal to a charge of 1 electron, but the sign is different.</em>
The proton is positively charged (+1), the electron is negatively charged (-1). and neutrons not charged (neutral)
Charge of 1 electron = e = -1.66.10⁻¹⁹ coulomb
Whereas the neutron charge = 0
<h3>Learn more </h3>subatomic particles in an atom
the three particles of an atom
neutrons
the mass, charge, and location of protons, neutrons, and electrons in atoms brainly.com/question/3294412
Keywords: protons, neutrons, electrons, subatomic particles, coulomb
You might be interested in
Archimedes' principle allows us to find that the reasons why the thrust is not written when a body is in the air is:
- The thrust of air is about 800 times less than the thrust of a fluid
- In general the other forces (weight, tension) are much greater than thrust
Archimedes' principle establishes that the thrust is equal to the weight of the dislodged liquid (fluid)
B = ρ g V
Where B is the thrust, ρ and V the density and volume of the fluid, respectively, g the acceleration due to gravity.
In the attachment you have a diagram of a system in equilibrium in air and water, we can see that in the two cases for a system in equilibrium
B -W = 0
B = W
Let's find the value of the thrust in each case and compare
Used the density
Suppose that the volume of the two bodies is the same
r
We can see that the thrust in air or other gas is about 800 times less than the thrust in liquids. This is the reason that in many problems the thrust is not written when the body is in the air.
In conclusion, using Archimedes' principle, we find that the reason why the healed thrust is not written for a body is in the air is:
- The thrust of air is about 800 times less than the thrust of a fluid
- In general the other forces (weight, tension) are much greater than thrust
Learn more about Archimedes' principle here:
Answer:
0.1
Explanation:
From the given question;