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3 years ago

Compared to the charge of a proton, the charge of all electron has

Chemistry

2 answers:

Vanyuwa [196]3 years ago

8 0

The charge of a proton and the charge of all electron has<u><em> (4) the same magnitude and the opposite sign</em></u>

<h3>Further explanation</h3>

Inside the atom consists of a nucleus containing 3 basic particles namely protons and neutrons, while electrons circulate the nucleus on a particular path so that electrons are not attracted to the nucleus.

The charge of these three atomic particles is based on the Rutherford experiment. Rutherford experimented with firing alpha rays on a thin gold plate. From this experiment it was found that:

1. Most alpha rays are passed through the gold plate, so it is concluded that most of the space in the atom has empty space

2. A small number of alpha particles deflected shows there are positively charged particles inside the atom

(at this time these particles are called protons located in the atomic nucleus)

From here comes the Rutherford atomic model which states that atoms consist of positively charged particles (protons) and negatively charged electrons around the nucleus.

<em>The charge of 1 proton is equal to a charge of 1 electron, but the sign is different.</em>

The proton is positively charged (+1), the electron is negatively charged (-1). and neutrons not charged (neutral)

Charge of 1 electron = e = -1.66.10⁻¹⁹ coulomb

Whereas the neutron charge = 0

<h3>Learn more </h3>

subatomic particles in an atom

brainly.com/question/4636746

the three particles of an atom

brainly.com/question/439508

neutrons

brainly.com/question/10905256

the mass, charge, and location of protons, neutrons, and electrons in atoms brainly.com/question/3294412

Keywords: protons, neutrons, electrons, subatomic particles, coulomb

Kay [80]3 years ago

6 0

<span>Answer: option (4) the same magnitude and the opposite sign.
</span>
Justification:
<span /><span /><span>
</span><span>1) Electrons are negative particles thar are around the nucleus of the atom (in regions called orbitals).
</span>
<span /><span /><span>
2) Protons are positive particles that are inside the nuclus of the atom.
</span><span />

<span>3) The nucleus of the atom has the same number of protons as electrons are in the orbitals of the atom.
</span>
<span /><span /><span>
4) The atoms are neutral (neither positive nor negative) because there are the same number of electrons and protons and their charge are of the same magnitude but different sign: (+) + (-) = 0: positive + negative = neutral.</span>

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In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an ex

Kay [80]

The question is incomplete. The complete question is :

In science, we like to develop explanations that we can use to predict the outcome of events and phenomena. Try to develop an explanation that tells how much NaOH needs to be added to a beaker of HCl to cause the color to change. Your explanation can be something like: The color change will occur when [some amount] of NaOH is added because the color change occurs when [some condition]. The goal for your explanation is that it describes the outcome of this example, but can also be used to predict the outcome of other examples of this phenomenon. Here's an example explanation: The color of the solution will change when 40 ml of NaOH is added to a beaker of HCl because the color always changes when 40ml of base is added. Although this explanation works for this example, it probably won't work in examples where the flask contains a different amount of HCl, such as 30ml. Try to make an explanation that accurately predicts the outcome of other versions of this phenomenon.

Solution :

Consider the equation of the reaction between NaOH and $HCl$

NaOH (aq) + HCl (aq) → NaCl(aq) + $H_2O (l)$

The above equation tells us that $1 \text{mole}$ of $NaOH$ reacts with $1 \text{mole}$ of $HCl$ .

So at the equivalence point, the moles of NaOH added = moles of $HCl$ present.

If the volume of the $HCl$ taken = $V_1$ mL and the conc. of $HCl$ = $M_1$ mole/L

The volume of NaOH added up to the color change = $V_2 \text{ and conc of NaOH = M}_2$ mole/L

Moles of $HCl$ taken = $V_1 \ mL \times M_1 \ mol/100 \ mL = V_2M_2 \times 10^{-3}$ moles.

The color change will occur when the moles of NaOH added is equal to the moles of $HCl$ taken.

Thus when $V_1 M_1 \times 10^{-3} = V_2M_2 \times 10^{-3}$

or when $V_1M_1 = V_2M_2$

or $V_2=\frac{V_1M_1}{M_2}$ mL of NaOH added, we observe the color change.

Where $V_1, M_1$ are the volume and molarity of the $HCl$ taken.

$M_2$ is the molarity of NaOH added.

When both the NaOH and $HCl$ are of the same concentrations, i.e. if $M_1=M_2$ , then $V_2=V_1$

Or the 40 mL of $HCl$ will need 40 mL of NaOH for a color change and

30 mL of $HCl$ would need 30 mL of NaOH for the color change (provided the concentration $M_1=M_2$ )

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pentagon [3]

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