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marusya05 [52]
3 years ago
11

1. What is the theoretical
 yield of C6H5Br in this reaction when 30.0 g of C6H6
reacts with excess Br2? If the 
actual yield of

C6H5Br was 56.7 
g, 
what 
is
 the 
percent 
yield?
Chemistry
1 answer:
Rudiy273 years ago
5 0

Answer:

The theoretical yield in grams is 60.292 grams, and in moles the theoretical yield is 0.384. The percent yield is 94%.

Explanation:

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no. of atoms in 0.044moles

no. of atoms =no. of moles x avogadro's number

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Day has 246060=86400 s

That means that 2,66x10^21  atoms of Ra produces 3,16 x10^15  atoms of Rn in a day.

N(Rn)=3.16* 10 ^15                           n(Rn)=N/NA

n(Rn)=5,25*10−9                              pV=nR*T

T=273.15K                                        R=8,314

p=101325Pa                                      V=n∗R∗T/p

V=5.25∗10^−9 ∗ 8.314 ∗ 273.15  /  101325

V=1.1810^−10 m^3 =   118 x10^-7 liters of Rn, measured at STP, are produced per day by 1.0 g of Ra

To know more about Ra here

brainly.com/question/9112754

#SPJ4

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