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marusya05 [52]
3 years ago
11

1. What is the theoretical
 yield of C6H5Br in this reaction when 30.0 g of C6H6
reacts with excess Br2? If the 
actual yield of

C6H5Br was 56.7 
g, 
what 
is
 the 
percent 
yield?
Chemistry
1 answer:
Rudiy273 years ago
5 0

Answer:

The theoretical yield in grams is 60.292 grams, and in moles the theoretical yield is 0.384. The percent yield is 94%.

Explanation:

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What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a
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\boxed {\boxed {\sf 333 \ grams}}

Explanation:

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The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

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4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)

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4500.0 \ J = m (13.52694 J/g)

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}

The units of Joules cancel.

\frac {4500.0 \ J }{13.52694 J/g}= m

332.6694729 \ g =m

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