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MaRussiya [10]
3 years ago
13

5. List four examples of neutralization reactions and four for acid-base reactions. You can revisit last week's lesson #

Chemistry
1 answer:
garik1379 [7]3 years ago
7 0

Answer:

Reacciones de neutralización

Mg(OH)2

NaHCO3

Bicarbonato de sodio

Cloruro de sodio

Reacciones acido base

HCl + NaOH → NaCl + H2O.

H2SO4 + 2 NaOH → Na2SO4 + H2O.

HCl + NH3 → NH4Cl + H2O.

HCN + NaOH → NaCN + H2O.

Explanation:

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2
Katyanochek1 [597]
C because a compound is a substance made of at least two atoms bonded together
4 0
3 years ago
What are chylomicrons? a. Alcohols with three-carbon chains b. Nitrogen compounds found in foods and made in the body c. Food ad
Artyom0805 [142]

Answer: Option C

Explanation:

Chylomicron is a small fat globule which is made of protein and lipids. These substances are found in the lymphatic fluid and blood where they tend to transport fat from the entry in the intestine to the liver and adipose tissue.

Once, one eats the fatty meal the blood is full of a number of chylomicrons which provides the blood texture.

The food that is digested is absorbed and transported to various parts of the body.

7 0
3 years ago
How many atoms are in 8.66 moles of barium? Round your answer to 2 decimal places.
yarga [219]

Answer:

52.15 × 10²³ atoms

Explanation:

Given data:

Number of moles = 8.66 mol

Number of atoms = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

1 mole = 6.022 × 10²³ atoms

8.66 mol × 6.022 × 10²³ atoms / 1mol

52.15 × 10²³ atoms

3 0
2 years ago
How many moles are in 715.11 grams of Ca(C2H302)2?
nikdorinn [45]

Answer:

4.52 mol

Explanation:

We do grams/Molar Mass to find the number of moles. The grams are given but the molar mass, you have to add all masses of the elements up by refering to a periodic table, and you should get that the compound has a mass of 158.168. Do 715.11 dived by that and you get the answer above.

3 0
3 years ago
When aqueous solutions of manganese(II) iodide and sodium phosphate are combined, solid manganese(II) phosphate and a solution o
Feliz [49]

Answer:

The net ionic equation for the given reaction :

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

Explanation:

3MnI_2(aq)+2Na_3PO_4_2(aq)\rightarrow Mn_3(PO_4)_2(s)+6NaI(aq)...[1]

MnI_2(aq)\rightarrow Mn^{2+}(aq)+2I^-(aq)..[2]

Na_3PO_4(aq)\rightarrow 3Na^{+}(aq)+PO_4^{3-}(aq)...[3]

NaI(aq)\rightarrow Na^+(aq)+I^-(aq)

Replacing MnI_2(aq) , NaI and Na_3PO_4(aq) in [1] by usig [2] [3] and [4]

3Mn^{2+}(aq)+6I^-(aq)+6Na^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)+6Na^+(aq)+6I^-(aq)

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

8 0
3 years ago
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