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2 years ago

Which equation would you use to calculate how much work is done in pushing a rock to the edge of the cliff?

Physics

1 answer:

Natalka [10]2 years ago

4 0

Answer:

Explanation:

d because a b c are energy equation not work

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I’ve already figured out A. I just need help with B and C.

Damm [24]

Answer:

595433.00

1456543.00

Explanation:

7 0

3 years ago

A 3.0-kg brick rests on a perfectly smooth ramp inclined at 34° above the horizontal. The brick is kept from sliding down the pl

Firdavs [7]

Answer:

d=0.137 m ⇒13.7 cm

Explanation:

Given data

m (Mass)=3.0 kg

α(incline) =34°

Spring Constant (force constant)=120 N/m

d (distance)=?

Solution

F=mg

F=(3.0)(9.8)

F=29.4 N

As we also know that

Force parallel to the incline=FSinα

F=29.4×Sin(34)

F=16.44 N

d(distance)=F/Spring Constant

d(distance)=16.44/120

d(distance)=0.137 m ⇒13.7 cm

4 0

3 years ago

What happens to the energy of a photon if the wavelength is doubled?.

Vladimir [108]

Answer:

Halving the wavelength doubles the frequency and, thus, doubles the energy of the incident photons. This doubles the energy given to each electron, nearly doubling its kinetic energy after it is free from the metal.

8 0

2 years ago

A fishing boat uses a sonar device which sends sound waves to the water that travel at 1000 m/s. The fishing boat detects a sign

Alexeev081 [22]

I think its D answer

sorry I dont have explanation but I think its D

6 0

2 years ago

A 60 kg boy and 40 kg girl stand on skateboards on a frictionless horizontal surface. The boy pushes the girl away from him. The

bezimeni [28]

Here in the above situation when boy pushes the girl there will be equal and opposite force on boy as per Newton's III law.

Due to this action reaction law boy will also go back with some speed.

Since there is no external force on this girl + boy system so we can use momentum conservation principle here.

As per momentum conservation

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

$60*0 + 40*0 = 60*v_{1f} + 40*0.3$

$0 = 60*v_{1f}+ 12$

$v_{1f} = -0.2 m/s$

So boy will go back with speed 0.2 m/s

Part b)

Since the boy and girl will always exert same force on each other by Newton's III law so it has no it matter whether the boy pushed the girl, the girl pushed the boy, or they put their hands together and pushed each other away.

As in all above cases the as per Newton's III law the force on them is always equal and opposite.

6 0

2 years ago