58/2=29
29 is prime
prime factorization is 2 times 29
Answer:
19.8 minutes
Step-by-step explanation:
Total time the 4 laps was completed = 4 x 2.5 = 10 minutes
Total time the 2 laps was completed = 2 x 4.9 = 9.8 minutes
total time = 10 minutes + 9.8 minutes = 19.8 minutes
To solve this problem you must apply the proccedure shown below:
1. Clear the radius from the formula for the circumference of a circle and substitute values, as following:

2. Substitute the radius calculated into the formula for calculate the surface area of the sphere:

The answer is: 
Answer:
Can you state in question in words. I cant see the picture.
Step-by-step explanation:
Answer:
r = 144 units
Step-by-step explanation:
The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.
Substituting the terms of the equation and the derivative of r´, as follows,

Doing the operations inside of the brackets the derivatives are:
1 ) 
2) 
Entering these values of the integral is

It is possible to factorize the quadratic function and the integral can reduced as,

Thus, evaluate from 0 to 16
The value is 