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zepelin [54]
4 years ago
15

Describe how the series and parallel circuits are different in terms of the direction the electrons flow in the circuit.

Physics
1 answer:
Musya8 [376]4 years ago
3 0

Answer:

In a series circuit, all components are connected end-to-end, forming a single path for current flow. In a parallel circuit, all components are connected across each other, forming exactly two sets of electrically common points.

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Clarissa has a credit card with a limit of $1,000 and pays her balance in full each month. If Clarissa needs a short-term loan,
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B.she cannot use it because the credit card is not collareral

Explanation:

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The charge density of a uniformly charged disk 0.420 m in diameter is 2.92 ✕ 10−2 C/m2. What is the magnitude of the electric fi
iragen [17]

Answer:

E = {(Charge Density/2e0)*(1 - [z/(sqrt(z^2 - R^2))]}

R is radius = Diameter/2 = 0.210m.

At z = 0.2m,

Put z = 0.2m, and charge density = 2.92 x 10^-2C/m2, and constant value e0 in the equation,

E can be calculated at distance 0.2m away from the centre of the disk.

Put z = 0.3m and all other values in the equation,

E can be calculated at distance 0.3m away from the centre of the disk

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3 years ago
Which of the following occurs when light is reflected from a rough or unpolished surface
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3 years ago
Water is flowing in a fire hose with a velocity of 1.0 m/s and a pressure of 200000 Pa. At the nozzle the pressure decreases to
jeka57 [31]

Answer:

The velocity is v_n  =14.09 \ m/s

Explanation:

From the question we are told that

    The velocity of the water in the pipe is  v_i =  1.0 \ m/s

     The pressure inside the pipe  is  P_i  = 200000 \ Pa

      The pressure at the nozzle is  P_n  =  101300 \ Pa

       The density of water is  \rho  =  1000 \ kg / m^3

      For the height h_1 = h_2 = h

where  h_1 is height of water in the pipe

  and  h_2 is height of water at the nozzle

Generally Bernoulli equation is represented as

       \frac{1}{2} \rho * v_i ^2 + \rho * g * h_1 +  P_i =  \frac{1}{2} \rho v_n ^2 + \rho * g* h_2 + P_n

=>   \frac{1}{2} \rho * v_i ^2 + \rho * g * h +  P_1 =  \frac{1}{2} \rho v_n ^2 + \rho * g* h + P_2

Where v_n is the velocity of the water at the nozzle

Now  making  v_n  the subject

            v_n  =  \sqrt{\frac{2}{\rho} [ P_i - Pn + \frac{1}{2} \rho v_i^2}

substituting values

            v_n  =  \sqrt{\frac{2}{1000} [ 200000 - 101300 + \frac{1}{2} (1000 * (1.0)^2)}

           v_n  =14.09 \ m/s

     

6 0
4 years ago
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