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Lana71 [14]
3 years ago
15

What is the pOH of a solution with [OH'] = 9,0 x 10-7?

Chemistry
1 answer:
bearhunter [10]3 years ago
6 0

Answer: D (6.04) is the best answer

Explanation:

pOH = - log [OH⁻]

pOH = - log (9.0 x 10⁻⁷)

pOH = 6.0457

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