Answer:
a. 3,392.7 N
b. 3,392.7 N
Explanation:
We are given the following information;
- Mass of the truck as 1052 kg
- initial speed as 0 m/s
- Final speed as 20.0 m/s
- Time taken as 6.20 s
#a. We are required to calculate the acceleration;
We need to know the formula of getting acceleration;
a = (v-u)/t
Where v is the final velocity, u is the initial velocity
Therefore;
a = (20 m/s - 0 m/s)/6.20s
= 3.225 m/s²
Thus, the average acceleration of the truck is 3.225 m/s²
#b. We are required to calculate the net force on the truck
We need to know that;
According to the second Newton's law of motion, F=ma
Where F is the net force, m is the mass and a is the acceleration.
Therefore;
Net force, F = mass × Acceleration
= 1052 kg × 3.225 m/s²
= 3,392.7 N
Thus, the net force on the truck is 3,392.7 N
140 ? i’m guessing there doesn’t look like there’s much to the question
Answer:
0.147 J
Explanation:
The total energy that has been transformed into thermal energy is equal to the loss of gravitational potential energy between the initial situation (bob at h=0.5 m above the ground) and the final situation (bob back but at h=0.45 m above the ground).
Therefore, we have
where
m = 0.3 kg is the mass of the bob
g = 9.8 m/s^2
h1 = 0.5 m is the initial height
h2 = 0.45 m is the final height
Substituting, we find the thermal energy
Therefore, the energy transformed into thermal energy is 0.147 J.
Answer:
D ko alam pasensya ka na ha
Answer:
Power=50.17dioptre
Power=50.17D
Explanation:
P=1/f = 1/d₀ + 1/d₁
Where d₀ = the eye's lens and the object distance= 5.70m=
d₁= the eye's lens and the image distance= 0.02m
f= focal length of the lense of the eye
We know that the object can be viewed clearly by the person ,then image and lens of the eye's distance needs to be equal with the retinal and the eye lens distance and this distance is given as 0.02m
Therefore, we can calculate the power using above formula
P= 1/5.70 + 1/0.02
Power=50.17dioptre
Therefore, the power the eye's is using to see the object from distance is 5.70D
