This is crazy. What’s 2+2?

How does the electric force between two charged particles change if the

Anuta_ua [19.1K]

C. It is decreased by a factor of 3.

3 0

3 years ago

Quickly Please!!!!!!

FrozenT [24]

Answer:

$n=4.1mol$

Explanation:

Hello,

In this case, we can use the ideal gas equation:

$PV=nRT$

So we know the temperature, pressure and volume, therefore we can easily compute the required moles as shown below:

$n=\frac{PV}{RT}=\frac{2.0atm*101L}{0.082\frac{atm*L}{mol*K}*600K} \\\\n=4.1mol$

Best regards.

5 0

3 years ago

Read 2 more answers

When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin

loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=8.2^0C$ = Depression in freezing point

$K_f$ = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality = $\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9$

$8.2^0C=1\times K_f\times 1.9$

$K_f=4.32^0C/m$

Now Depression in freezing point for sodium chloride is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=20.0^0C$ = Depression in freezing point

$K_f$ = freezing point constant

m= molality = $\frac{136g\times 1000}{950g\times 58.5g/mol}=2.45$

$20.0^0C=i\times 4.32^0C\times 2.45$

$i=1.9$

Thus vant hoff factor for sodium chloride in X is 1.9

3 0

3 years ago

An electron:

Korvikt [17]

It has a negative charge emits energy when it moves to a lower energy orbit from an excited state and it has the same mass as a proton

4 0

4 years ago

A monatomic ideal gas at a pressure of 1.00 atm expands adiabatically from an initial volume of 1.50 m3 to a final volume of 4.0

tamaranim1 [39]

The correct answer is 1atm.

<h3>What is Kinetic theory of gases?</h3>

A lot of the fundamental ideas of thermodynamics were established with the help of the kinetic theory of gases, a straightforward yet historically significant classical model of the thermodynamic behaviour of gases. According to the model, a gas is made up of numerous identical submicroscopic particles (atoms or molecules) that are all moving rapidly and randomly. It is considered that they are substantially smaller in size than the particle spacing on average. Random elastic collisions between the particles and with the container's walls occur between the particles. The simplest form of the model only takes into account the interactions within the ideal gas.

learn more about Kinetic theory of gases refer:

brainly.com/question/3924326

#SPJ4

7 0

2 years ago