Just measure the width (or height, if you'll be stacking the pennies
a mile high) of a penny, then divide 5280 feet by whatever you find.
This is a great activity for a class, and in fact a good way to start
the project. First take one penny, and work out an answer. Then get
100 pennies, and measure them; do the same calculation to see how many
pennies it will take to make a mile. There will probably be a
difference, because you can measure 100 pennies more accurately than a
single penny. Or maybe you have a micrometer that will measure one
penny precisely. Which is better can be a good discussion starter. And
don't forget to try it in metric, too.
Just to illustrate, using a very rough estimate of a penny's width,
let's say a penny is about 3/4 inch wide. The number of pennies in a
mile will be
5280 ft 12 in 1 penny
1 mile * ------- * ----- * ------- = 5280 * 12 * 4/3 pennies
1 mi 1 ft 3/4 in
This gives about 84,480 pennies. (This method of doing calculations
with units is very helpful, and would be worth teaching.)
If we measure 100 pennies as 6 ft 1 in, we will get
5280 ft 100 pennies
1 mile * ------- * ----------- = 5280 * 100 * 12 / 73 pennies
1 mi 6 1/12 ft
This gives us 86794.5205 pennies in a mile.
Answer:
C
Step-by-step explanation:
First multiply both sides by 7
Your equation now looks like this:
x-28=0
Now move the constant to the other side causing it to change signs
The negative now becomes a positive
x=28
Now you are left with your answer:
x=28
Hope this helps! :3
Answer:
The answer is 7.433
Step-by-step explanation:
Bc:
25.643 the 5 turned to 15, and the 2 is a 1.
- 18.210
7.433
Hope my answer has helped you, if not i'm sorry.
The domain will be every integer from 0 to 76867 (it will look like this [0, 76867].
The range will be <span>{0, 161, 322, 3(161), 4(161), ... 76867(161)}.</span>
With the information given, the equation will look like this:
f(x) = 161x
The domain is a set of all possible values that, when plugged into x, will give us a real number. So, if we were to plug in 2 for x, the equation would look like this:
f(2) = 161(2) = 322
Since 322 is a real number, 2 is part of the domain.
While the domain is the set of numbers that substitute x, the range is the product. So in the above example, the range would be 322. Since the domain is [0, 76867], the range would be the set of products that come from plugging in each of these numbers:
{0, 161, 322, 3(161), 4(161), ... 76867(161)}
