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nata0808 [166]
3 years ago
15

WITHOUT FRICTION, what happens to the skater if you release him from a height ABOVE the track?

Physics
1 answer:
ElenaW [278]3 years ago
3 0

Answer:

B, he will fly off the other end

Explanation:

there is too much potential energy that transforms into kinetic energy for him to stay on the track.

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Classify the type of plate boundary where the appalachian mountains formed . how have they changed since their formation
disa [49]
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6 0
3 years ago
What is the difference between distance and displacement? Give an example of a situation where distance and displacement both ha
Oksana_A [137]

Explanation :

Distance is total path travelled by an object during its entire journey. It is a scalar quantity i.e only magnitude.

Displacement is the shortest distance covered by an object. It is basically the change in position of object. It is a vector quantity i.e direction as well as magnitude.

When an object is travelling in a straight line and stops at the end point, then both distance and displacement are same.

When an object is travelling in a straight line and then changes its direction or we can say come backwards then the magnitude of distance and displacement are different.

4 0
3 years ago
A steel wire in a piano has a length of 0.680 m and a mass of 4.600 ✕ 10⁻³ kg. To what tension must this wire be stretched so th
garik1379 [7]

Answer:

728 N

Explanation:

L = length of the wire = 0.680 m

m = mass of the steel wire = 0.0046 kg

f = Fundamental frequency = 261.6 Hz

T = tension force in the steel wire

Fundamental frequency in wire is given as

f = \frac{1}{2L} \sqrt{\frac{TL}{m} } \\261.6 = \frac{1}{2(0.680)} \sqrt{\frac{T(0.80)}{0.0046} }\\(2) (0.680) (261.6) = \sqrt{\frac{T(0.80)}{0.0046} }\\355.8 = \sqrt{\frac{T(0.80)}{0.0046} }\\355.8^{2} = \frac{T(0.80)}{0.0046}\\T = \frac{(355.8^{2}(0.0046))}{0.80} \\T = 728 N

3 0
3 years ago
What percentage of the takeoff velocity did the plane gain when it reached the midpoint of the runway? a plane accelerates from
ElenaW [278]
When is at the end of the runway the velocity of the plane is given by the equation vf^{2}=0+2*a*s    where s=1800 m is the runway length. Thus
vf^{2}=2*5*1800=18000 (m/s)^{2}      
vf =134.164 (m/s)  

At half runway the velocity of the plane is
v^{2}=2*5* \frac{1800}{2}=9000 ( \frac{m}{s} )^{2}&#10; 
v= \sqrt{9000}=94.87 ( \frac{m}{s})

Therefore at midpoint of runway the percentage of takeoff velocity is
‰P= \frac{v}{vf}=  \frac{94.87}{134.164}=0.707
6 0
3 years ago
8. Mark is sitting in a chair, legs out in front of him resting on an ottoman. His knees are.....
anyanavicka [17]
His knees are flat in front of him or 180 degrees, i hope that answered your question   
5 0
3 years ago
Read 2 more answers
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