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Olin [163]
2 years ago
13

Calculate the oxidation state of the underlined elements of K2 Cr2 O7

Chemistry
1 answer:
Semenov [28]2 years ago
3 0

Answer:

+4

Explanation:

In PbO2, oxygen exhibits an oxidation number of -2 (since it's not a peroxide or superoxide):

Let the oxidation number of Pb be x. Then, for the compound to be neutral, the oxidation numbers of all atoms should add up to zero.

⇒ x + (−2) + (−2) = 0

x = +4

So the oxidation no. of Pb is +4.

I hope this helps.

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2) Molarity is number of mole of the solute in 1 L solution.
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(25/36.5 mol HCl )/(0.150 L) = 25/(36.5*0.150) ≈ 4.57≈4.6 mol/L


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