Answer:-0.4199 J/k
Explanation:
Given data
mass of nitrogen(m)=1.329 Kg
Initial pressure=120KPa
Initial temperature 300k
Final volume is half of initial
R=particular gas constant
Therefore initial volume of gas is given by
PV=mRT
V=0.986\times 10^{-3}
Using =constant
=
=337.066KPa
=
and entropy is given by
=
+
Where, =
=0.6059
=
=0.9027
Substituting values we get
=
+
=-0.4199 J/k
Answer:
the atomic radius of a lithium atom is 0.152 nm
Explanation:
Given data in question
structure = BCC
lattice constant (a) = 0.35092 nm
to find out
atomic radius of a lithium atom
solution
we know structure is BCC
for BCC radius formula is /4 × a
here we have known a value so we put a in radius formula
radius = /4 × a
radius = /4 × 0.35092
radius = 0.152 nm
so the atomic radius of a lithium atom is 0.152 nm