Answer:
The correct option is;
Materials and Components
Explanation:
The efficiency of fluid power is influenced by the components and the materials used to deliver the power of the fluid as such fluid power control are focused on
1) Advances in fluid power
2) Making use of the advantages
3) Making use of the other externally available technological advantages
4) Giving allowance for disadvantages
Areas of interest in advances in fluid power are;
a. Computer optimized flow
b. The use of new and improved materials/coatings
c. The use of components that save energy, such as intelligent supply pressure adapting systems
Answer:the first is wrong because the s
Explanation:
the second is fake
Answer:
isentropic efficiency = 0.818
Explanation:
given data
pressure P1 = 95 kPa
temperature = 27°C
pressure P2 = 600 kPa
temperature = 277°C
to find out
isentropic efficiency of the compressor and exit temperature of the air
solution
we know from ideal gas of properties of air is
Pr1 at 27°C = 1.3860
and h1 at 300 K = 300.19 kJ/kg
and h2 at 550 K = 555.74 kJ/kg
and
we know equation for isentropic process that is
.........................1
put here value we get
solve we get Pr2
Pr2 = 8.75
by ideal gas of properties of air will be at Pr2
h2s = 508.66
T2s = 505.5 K
'so
isentropic efficiency will be here as
isentropic efficiency =
isentropic efficiency =
isentropic efficiency = 0.818
Answer:
1.80 m
Mezzanine floors shall have a clear ceiling height of not less than 1.80 m above and below it.
Explanation:
Hope it helps
Answer:
<em>The normal stress is 0.7821 MPa</em>
<em></em>
Explanation:
The external diameter D = 160 mm
The thickness t = 3.8 mm = 3.8 x 10^-3 m
gauge pressure P = 78 kPa = 78 x 10^3 Pa
The maximum shear stress τmax = ?
The external radius of the shell from the external surface R = D/2 = 160/2 = 80 mm
The internal radius of the shell r = R - t
==> 80 - 3.8 = 76.2 mm
Therefore the internal diameter d = 2r = 2 x 76.2 = 152.4 mm
==> d = 152.4 x 10^-3 m
The normal stress σ = = = 782052.63 Pa
==> σ = <em>0.7821 MPa</em>