Answer:
See explanation
Explanation:
The question is incomplete because the image of the alcohol is missing. However, I will try give you a general picture of the reaction known as hydroboration of alkenes.
This reaction occurs in two steps. In the first step, -BH2 and H add to the same face of the double bond (syn addition).
In the second step, alkaline hydrogen peroxide is added and the alcohol is formed.
Note that the BH2 and H adds to the two atoms of the double bond. The final product of the reaction appears as if water was added to the original alkene following an anti-Markovnikov mechanism.
Steric hindrance is known to play a major role in this reaction as good yield of the anti-Markovnikov like product is obtained with alkenes having one of the carbon atoms of the double bond significantly hindered.
Answer:
2Al + 6H2O --> 2Al(H2O)3 + 3H2
Explanation:
aAl + bH2O --> cAl(H2O)3 + dH2
To balance this equation, the Al(H2O)3 is first multiplied by c = 2 to even out the water molecule.
Since we have done that, the reactant water molecule is balenced with b = 3 so that the difference in the Hydrogen in the aluminum hydroxide molecule and the reactant water molecule, which is 6 goes to the H2 (d = 3) in the product.
Then, the Al metal is balanced with a = 2 and then the reaction is balanced.
2Al + 6H2O --> 2Al(H2O) + 3H2
Proton number of a particular atom
The answer is D I hope this helps you !
4 Quantum numbers are used
1.Azimuthal
2.Principal
3.Spin
4.Magnetic
