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inn [45]
3 years ago
7

A mystery element contains 11 electrons. Which group of the periodic table will it belong to?

Chemistry
1 answer:
serious [3.7K]3 years ago
7 0
There are 18 Elements in the fifth period.
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2. 7.5 g of potassium react with water to produce potassium hydroxide and hydrogen gas. Calculate the mass of potassium hydroxid
luda_lava [24]

Answer:

10.7 g of KOH

Explanation:

First of all, we determine the reaction:

2K (s) + 2H₂O(l) → H₂(g) + 2KOH(aq)

We convert the mass of K, to moles → 7.5 g . mol/39.1 g = 0.192 moles

Ratio is 2:2, so the moles I have of K must produce the same moles of KOH. In this case, the produces moles of KOH are 0.192 moles.

We convert the moles to mass, to finish the answer:

0.192 mol . 56.1g /1mol = 10.7 g of KOH

8 0
3 years ago
Plants are considered
wariber [46]
Because they create their own food, they are considered as producers.
6 0
2 years ago
What is bias?
Maru [420]

Answer:

B

Explanation:

bias is when you want something to be true so you might ignore evidence to make your conclusion what you want it to be.

4 0
2 years ago
A balloon sits in the sunlight causing it to heat up and explode. Which of the following
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I think it’s A, the particles of gas inside the ballon move faster and decrease pressure in
6 0
1 year ago
If 16.9 kg of Al2O3(s), 57.4 kg of NaOH(l), and 57.4 kg of HF(g) react completely, how many kilograms of cryolite will be produc
hodyreva [135]

Answer: 69.72 kg of cryolite will be produced.

Explanation:

The balanced chemical equation is:

Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of Al_2O_3 = \frac{16.9\times 1000g}{102g/mol}=165.7moles

moles of NaOH = \frac{57.4\times 1000g}{40g/mol}=1435moles

moles of HF = \frac{57.4\times 1000g}{20g/mol}=2870moles

As 1 mole of Al_2O_3 reacts with 6 moles of NaOH

166 moles of  Al_2O_3 reacts with = \frac{6}{1}\times 166=996 moles of NaOH

As 1 mole of Al_2O_3 reacts with 12 moles of HF

166 moles of  Al_2O_3 reacts with = \frac{12}{1}\times 166=1992 moles of HF

Thus Al_2O_3 is the limiting reagent.

As 1 mole of Al_2O_3 produces = 2 moles of cryolite

166 moles of  Al_2O_3 reacts with = \frac{2}{1}\times 166=332 moles of cryolite

Mass of cryolite (Na_3AlF_6) = moles\times {\text {molar mass}}=332mol\times 210g/mol=69720g=69.72kg

Thus 69.72 kg of cryolite will be produced.

8 0
3 years ago
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