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pantera1 [17]
3 years ago
6

What is an effect of La Nina?

Physics
1 answer:
givi [52]3 years ago
4 0

Answer:

D.) South American becomes dire than normal

Explanation:

La Niña effect can be regarded as an effect that has impacts on the global climate, this effect bring about disruption in normal weather patterns, as a result of this intense storms as well as drought is experienced. The effect could be intense by worsening of above temperature. It bring an increases the probability of having a rainfall below normal. As a result of this

South American becomes dire than normal.

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Which list places the layers of the sun in the correct order from outermost to innermost?
Valentin [98]
Answer - corona, chromosphere, photosphere
4 0
3 years ago
A net force of 50 newtons is applied to a 20 kilogram cart that is already moving at 1 m/s the final speed of the cart was 3 m/s
valina [46]

Answer:

0.8 seconds

Explanation:

F=ma

Let x be the seconds the force is applied.

m = 20kg

F = 50 Newtons (kg*m/sec^2)

acceleration, a, is provided for x seconds to increase the speed from 1 m/s to  3 m/s, an increase of 2m/s

Let's calculate the acceleration of the cart:

F=ma

(50 kg*m/s^2) = (20kg)*a

a = 2.5 m/s^2

---

The acceleration is 2.5 m/s^2.  The cart increases speed by 2.5 m/s every second.  

We want the number of seconds it takes to add 2.0 m/sec to the speed:

(2.5 m/s^2)*x = 2.0 m/s

x = (2.0/2.5) sec

x = 0.8 seconds

7 0
3 years ago
Given the equation p2 = a3, what is the orbital period, in days, for the planet venus? (venus is located 0.72 au from the sun?)
melisa1 [442]

The correct answer is 223 days.

The relationship between the duration of revolution and the separation between the sun is shown by Kepler's third law. Using the notions of circular motion and the gravitational and centripetal forces, we may obtain this equation.

According to Kepler's third rule, the semi-major axis of an orbit is linked to the orbital period of a planet around the sun as follows:

p² = a³

where an is the semi-major axis/distance to the star and p is the orbital period in years.

It is said that a = 0.72 AU for Venus.

P= √(0.72 AU)^3 = 0.61 years.

365 days in a year = 222.9 ≈ 223 days.

To learn more about Kepler's third rule refer the link:
brainly.com/question/1608361

#SPJ4

5 0
1 year ago
A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.4 m/s, a typical raindrop speed. How fast
kenny6666 [7]

The final velocity after the collision is 8.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.

If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.

Mathematically:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 is the mass of the first mosquito

u_1 = 0 is the initial velocity of the mosquito

m_2 = 50 m_1 is the mass of the raindrop

u_2 = 8.4 m/s is the initial velocity of the raindrop

v is the final combined velocity of the raindrop+mosquito

Re-arranging the equation and substituting, we find:  

m_1 u_1 + 50 m_1 u_2 = (m_1 + 50 m_1) v\\50 m_1 u_2 = 51 m_1 v\\50 u_2 = 51 v\\v=\frac{50}{51}u_2 = \frac{50}{51}(8.4)=8.2 m/s

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

4 0
3 years ago
a baseball player is dashing toward home plate with a speed of 200 feet per hour. When he decides to hit the dirt. he slides for
Serggg [28]

To solve this problem we will use the kinematic formula for the final velocity.


V_f_x = V_0_x + a_xt


The final speed is 0 at the moment the player stops.


The time until it stops is 1.3 s


The initial speed is 200 feet / s  Note (check the speed units in the problem statement, 200ft / s is very much and 200ft / h is very small)

Then, we clear the formula.


a_x = \frac{(Vfx-V0x)}{t}\\ a_x = \frac{(0-200)}{1.3}\\ a_x = -153.5 ft / s ^ 2

Because the player is slowing down, the acceleration goes in the opposite direction to the player's movement, and that is why it is negative.



To answer part b) we use the following formula.


Vf ^ 2 = Vo ^ 2 + 2a * (x_2 - x_1)\\\\ (x_2 - x_1)= \frac{(V_f ^ 2-V_0 ^ 2)}{2a}\\\\ (x_2 - x_1)= \frac{(0-200 ^ 2)}{- 2 * 153.5}\\\\ (x_2 - x_1)= 130.29 feet

8 0
3 years ago
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