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jekas [21]
3 years ago
13

Q1. Which reaction represents the half-reaction of lead (Pb) and the SRP value that could be found on an electric potential tabl

e?
Q2.Which value represents the standard cell potential of the spontaneous overall reaction?

Chemistry
1 answer:
iris [78.8K]3 years ago
3 0
The reaction that represents the half-reaction of lead Pb is    
    Pb2+(aq) + 2e- → Pb(s)   
and the SRP value on electric potential table is -0.13V.

To find the overall potential of a reaction, two half reactions can be added
together:
Oxidation:           Fe(s) → Fe2+(aq) + 2e-                               +0.44V
Reduction:          Pb2+(aq) + 2e- → Pb(s)                               - 0.13 V      
Overall reaction: Fe(s) + Pb2+(aq) → Pb(s) + Fe2+(aq)         +0.31V

This positive voltage for the overall reaction is spontaneous.

You might be interested in
When 1.045 g of CaO is added to 50.0 mL of water at 25.0 °C in a calorimeter, the temperature of the water increases to 32.3 °C.
Rus_ich [418]

Answer:

1.71 kJ/mol

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of CaO = 1.045 g

Specific heat = 4.18 J/g°C

\Delta T=32.3-25.0\ ^0C=7.3\ ^0C

So,  

\Delta H=1.045\times 4.18\times 7.3\ J=31.88713\ J

Also, 1 J = 0.001 kJ

So,  

\Delta H=0.03189\ kJ

Also, Molar mass of CaO = 56.0774 g/mol

Moles=\frac{Mass}{Molar\ mass}=\frac{1.045}{56.0774}\ mol=0.01863\ mol

Thus, Enthalpy change in kJ/mol is:-

\Delta H=\frac{0.03189}{0.01863}\ kJ/mol=1.71\ kJ/mol

8 0
2 years ago
Calculate the oxidation number for carbon in CH4
Maksim231197 [3]

Answer:

+4

Explanation:

Oxidation number of neutral compound is 0

Oxidation number of hydrogen in methane is -1

C + (-1×4) = 0

C - 4 = 0

C = 4

8 0
2 years ago
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Murljashka [212]

Answer:

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Explanation:

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4 0
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Answer:

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Explanation:

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3 years ago
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DerKrebs [107]

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