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jekas [21]
3 years ago
13

Q1. Which reaction represents the half-reaction of lead (Pb) and the SRP value that could be found on an electric potential tabl

e?
Q2.Which value represents the standard cell potential of the spontaneous overall reaction?

Chemistry
1 answer:
iris [78.8K]3 years ago
3 0
The reaction that represents the half-reaction of lead Pb is    
    Pb2+(aq) + 2e- → Pb(s)   
and the SRP value on electric potential table is -0.13V.

To find the overall potential of a reaction, two half reactions can be added
together:
Oxidation:           Fe(s) → Fe2+(aq) + 2e-                               +0.44V
Reduction:          Pb2+(aq) + 2e- → Pb(s)                               - 0.13 V      
Overall reaction: Fe(s) + Pb2+(aq) → Pb(s) + Fe2+(aq)         +0.31V

This positive voltage for the overall reaction is spontaneous.

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Liquids have a(n)____shape and A(n)_____volume.
shusha [124]
B. Indefinite, definite
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3 years ago
Convert 1000mg=__g 1L=__mL 160cm=__mm 1.4km=__m 109g=__kg 250m=__km 80cm=__m 75mL=__L 5.6m=__cm 6.5g=__mg 170.4m=__cm 564Dg=__g
Snowcat [4.5K]

Answer:

1000mg= 1g

1L= 1000 mL

160cm = 1600mm

1.4km= 1400m

109 g = 0.109kg

250m= 0.250 km

80cm= 0.8 m

75mL= 0.075L

5.6m= 560 cm

6.5g= 6500mg

170.4m= 17040 cm

564 Dg = 5640 g

58 dg = 5800 mg

600 L=  0.6 KL

0.0923Km= 92300 mm

Explanation:

1 mg = 1x10⁻³ g

1 g = 1000 mg

1 g = 10 dg

1 g = 1x10⁻³ kg

1 Dg = 10 g

1 dg = 100 mg

1 L = 1000 mL

1 L = 1x10⁻³ KL

1 mL = 1x10⁻³ L

1 km = 1000 m

1 km = 1x10⁶ mm

1 m = 1x10⁻³ km

1 cm = 1x10⁻² m

1 cm = 10 mm

5 0
3 years ago
A chemist determined by measurements that 0.030 moles of barium participated in a chemical reaction. Calculate the mass of bariu
schepotkina [342]

Answer: 4.1 g of barium precipitated.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}

Given : moles of barium = 0.030

Molar mass of barium = 137 g/mol

0.030=\frac{x}{137}

x= 4.1 g

Thus there are 4.1 g of barium that precipitated.

3 0
3 years ago
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