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Tcecarenko [31]
2 years ago
14

What is the reactant of 2Fe2O3 = 4Fe + 3O2

Chemistry
1 answer:
Anit [1.1K]2 years ago
3 0

It depends on the direction of the arrow.

If the arrow goes like this ---> the reactant would be 2Fe2O3

If the arrow goes like this <--- the reactants would be 4Fe + 3O2

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Which characteristic of living organisms is described by the following definition? "The ability
saw5 [17]
3 I don’t know but it may be movement
3 0
2 years ago
What’s the chemical formula for lithium carbonate
nordsb [41]

Answer:

<h3>Being a science geek the ans is <u><em>Li2CO3</em></u></h3>

Explanation:

8 0
2 years ago
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When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find
ryzh [129]
The balanced equation is 
4Fe+3O₂⇒2Fe₂O₃

We know that the mole of Fe₂O₃ is 6, and since the ratio between oxygen and <span>Fe₂O₃ is 3:2, we can see that

3:2 = x:6 (3 oxygen moles can make 2 </span>Fe₂O₃ moles = x oxygen moles can make 6 <span>Fe₂O₃ moles)
</span><span>
Multiply outside and inside (3*6 , 2*x) and put them on opposing sides of the equation

2*x = 3*6
2x=18
x=9
Therefore 9 moles of oxygen is needed.

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6 0
2 years ago
Read 2 more answers
Atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron. giv
valina [46]

Answer:

Option A is correct.

Atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron

Explanation:

Atomic orbitals developed using quantum mechanics make use of quantum numbers.

There are four different quantum numbers that all work to give the region of space where a particular electron has the highest probability of being located.

The four quantum numbers that describes an electron's most likely location in an atom include

1) Principal quantum number, denoted by letter n. This quantum number gives the shell that an electron in an atom belongs to. It can take on natural number values from 1 (for the shell closest to the nucleus) through 2, 3, 4.... till rhe outermost shell.

2) Azimuthal/Angular Momentum quantum number, denoted by l. This quantum number describes the subshell or orbital within a shell that the electron belongs to in an atom.

It can take on values that can range from 0 to (n-1). These are the spdf orbitals with s-orbital having l-quantum number of 0, p-orbital with l-quantum number of 1 etc.

3) Magnetic quantum number, denoted by letter m. This describes the sub-orbital that the electron belongs to. It's values for electrons in a particular orbital vary from -l through 0 to +l.

E.g. orbital with l = 1 has electrons whose magnetic quantum number vary from -1, 0, +1.

orbital with l = 2 has electrons whose magnetic quantum number vary from -2, -1, 0, +1, +2.

4) Spin quantum number, denoted by letter s.

This describes the orientation of the electron's spin. Whether clockwise or anti-clockwise in it's sub-orbital. It can take on only values of (+1/2) or (-1/2).

So, these four quantum numbers, numbers that were made known because of quantum mechanics, show that atomic orbitals developed using quantum mechanics describe regions of space in which one is most likely to find an electron in an atom.

Hope this Helps!!!

5 0
2 years ago
Bromine monochloride is synthesized using the reaction:
Sergeu [11.5K]

Answer:

11.72 grams

Explanation:

Let the equilibrium concentration of BrCl be y

Initial concentration of Br2 = number of moles ÷ volume = (0.979×1000/160) ÷ 199 = 0.031 M

Initial concentration of Cl2 = (1.075×1000/71) ÷ 199 = 0.076 M

From the equation of reaction

1 mole of Br2 reacted with 1 mole of Cl2 to form 2 moles of BrCl

Therefore, equilibrium concentration of Br2 = (0.031 - 0.5y) M while that of Cl2 = (0.076 - 0.5y) M

Kp = [BrCl]^2/[Br2][Cl2]

1.1×10^-4 = y^2/(0.031 - 0.5y)(0.076 - 0.5y)

y^2/0.002356-0.0535y+0.25y^2 = 0.00011

y^2/0.00011 = 0.002356-0.0536y+0.25y^2

9090.9y^2-0.25y^2+0.0536y-0.002356 = 0

9090.65y^2+0.0535y-0.002356 = 0

The value of y must be positive and is obtained using the quadratic formula

y = [-0.0535 + sqrt(0.0535^2 - 4×9090.65×-0.002356)] ÷ 2(9090.65) = 9.2025/18181.3 = 0.00051 M

Mass of BrCl = concentration×volume×MW = 0.00051×199×115.5 = 11.72 grams

4 0
3 years ago
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