<u>Answer:</u> The empirical formula for the given compound is 
<u>Explanation:</u>
We are given:
Mass of pure compound containing copper and sulfur = 4.963 g
Mass of S = 1.000 g
Mass of Cu = (4.963 - 1.000) g = 3.963 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Copper =
Moles of Sulfur = 
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0312 moles.
For Copper = 
For Sulfur = 
<u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of Cu : S = 2 : 1
Hence, the empirical formula for the given compound is 
Answer:
For mole conversion always remember 1 mole of compound = molar mass of compound.
Ex. 2 moles H20 to grams
2mol H2O x 18 g / 1mol H20
For molecules use Avogadro's number like moles multiplied to 6.022x10²³ answer will be in molecules.
Explanation:
Answer:
-490.7 K
Explanation:
Given:
[Ni^2+]= 0.4 M
[Pb^2+]=0.002 M
∆V= -0.012 V
VNi= -0.250V
VPb= -0.126V
F= 96500 C
R= 8.314 JK-1 mol-1
n= 2
From
T= -nF/R [∆V-(VNi-VPb)/ln [Pb2+]/[Ni2+]]
T= 2(96500)/8.314[ (-0.012) -(-0.250) - (-0.126))/ln[0.002]/[0.4]
T= 23213.856(0.112/(-5.298))
T= -490.7 K
Answer: KI> Al(NO3)3> HF> CH3OH
Explanation:
Potassium iodide is a halide of group 1 which is very soluble in water and whose ions are very mobile in solution. It will readily dissociate and conduct electricity making the bulb brightest when KI is the electrolyte. Salts of group 13 are not as ionic as those of group 1 but dissociate appreciably and conduct electricity. HF is a halogen acid but self ionizes and shows some degree of conductivity. Methanol will have the lowest conductivity making the bulb dimmest when methanol is the electrolyte.
Answer:
The rice will move
Explanation:
the sound vibration and waves will cause the rice to move